pyrex graduated cylinder has a volume of exactly 200 ml at 0° celsius. if it's temperature increased to 100° celsius what's volume increase or decrease compute the change in volume ?
Answers
1. The volume will increase.
2. The change in the volume is 73 mL
1. Determination of the nature of the new volume.
From the question given above, the following data were obtained:
- Initial volume (V₁) = 200 mL
- Initial temperature (T₁) = 0 °C = 0 + 273 = 273 K
- New temperature (T₂) = 100 °C = 100 + 273 = 373 K
- New volume (V₂) =?
Using the Charles' law equation, the new volume of the cylinder can be obtained as follow:
V₁ / T₁ = V₂ / T₂
200 / 273 = V₂ / 373
Cross multiply
273 × V₂ = 200 × 373
273 × V₂ = 74600
Divide both side by 273
V₂ = 74600 / 273
V₂ ≈ 273 mL
From the above calculation, we can see that the new volume increased.
2. Determination of the change in the volume.
The change in the volume can be obtained as illustrated below:
- Initial volume (V₁) = 200 mL
- New volume (V₂) = 273 mL
- Change in volume (ΔV) =?
ΔV = V₂ – V₁
ΔV = 273 – 200
ΔV = 73 mL
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Answer: the top layer of the saturated zone
Explanation: Water table is also called as the groundwater table.The water table is the level below the surface of the ground where water is found.
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The water table keeps changing with the seasons and from year to year because it is affected by climatic variations and by the amount of precipitation.
Final answer:
The water table is the upper boundary of the saturated zone where all pores in soil and rocks are completely filled with water. It fluctuates depending on weather, seasons, and human activities, and it exists within porous soil and rock rather than nonporous ones.
Explanation:
The water table is the top layer of the saturated zone found below the Earth's surface, where all open spaces in soil and rocks are filled with water. This boundary separates the unsaturated zone (also called the vadose zone) above, which contains both air and water, from the saturated zone beneath, where all pores and fractures are fully inundated with water. Although the water table fluctuates with changes in weather, season, and human activity, it is not made of nonporous soil and rock. Instead, it resides within porous soil and rock that allow water to percolate down from the surface.
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Answers
Answer:
Explanation:
Horizontal Launch
When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
vx=v
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
The horizontal component of the velocity is always the same:
The vertical component at t=5.5 s is:
Answers
120 kilometers is equivalent to 74.565 miles,
or 14.71% greater than 65 miles.
104.6067 kph x 115% = 120.3 kph (rounded)
120 kph is 115% faster than 65 mph.
Answers
The amount of thermal energy that is created in the slope and the tube during the ascent is 19680 Joules.
Given the following data:
- Total mass = 80 kg
- Tension = 360 Newton
- Height = 30 meters
- Displacement = 120 meters
To find the amount of thermal energy that is created in the slope and the tube during the ascent:
By applying the Law of Conservation of Energy:
Where:
- K.E is the kinetic energy.
- P.E is the potential energy.
- T.E is the thermal energy.
Since the rider and his tube are pulled at a constant speed, K.E is equal to zero (0).
Therefore, the formula now becomes:
For the work done:
Work done = 43,200 Joules.
For P.E:
P.E = 23,520 Joules.
Now, we can find the amount of thermal energy:
T.E = 19680 Joules.
Read more: brainly.com/question/22599382
Answer:
Explanation:
GIVEN DATA:
Total mass ( rider + his tube) = 80 kg
tension Force = 360 N
height of slope = 30 m
length of slope = 120 m
we know that thermal energy is given as
E_{th} = W- Ug
W= F*d = (360N*120m)= 43200 J
Ug= m*g*h = (80kg*9.8m/s2*30m) = 23520 J
Answers
Answer:
Displacement = 1725m
Explanation:
Final answer:
Using the equations of motion, we find that the plane covers a distance of 850 meters while it is accelerating from a velocity of 50 m/s to 65 m/s at the rate of 0.5 m/s².
Explanation:
You're asking about a motion problem in physics that requires using the equations of motion to solve. In this case, the formula we would use is v² = u² + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is acceleration, and 's' is the distance covered.
Given:
Initial velocity (u) = 50 m/s
Final velocity (v) = 65 m/s
Acceleration (a) = 0.5 m/s²
We are asked to find the distance covered (s). Rearranging the formula to find 's', we get: s = (v² - u²) / 2a
Substituting the given values, the distance covered (s) = (65² - 50²) / (2*0.5) = 850 meters. So, the plane covers a distance of 850 meters while it is accelerating.
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