The number of bacterial population after 5 hours is; 816
N(t) = N_o(1 + r)^(t)
Where;
N(t) is number of bacteria after t hours
N_o is number of bacteria initially
r is growth rate
t is time
N_o = 480
r = 11.2% = 0.112
t = 5
N(5) = 480(1 + 0.112)^(5)
N(5) = 816.14
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The bacterial population after 5 hours with an exponential growth rate of 11.2% per hour and an initial population of 480 bacteria would be approximately 947.1 bacteria.
To calculate the bacterial population after 5 hours with an exponential growth rate of 11.2% per hour and an initial population of 480 bacteria, we can use the formula
P = P0 * (1 + r)^t.
P is the final population, P0 is the initial population, r is the growth rate expressed as a decimal, and t is the time in hours.
Using the given values, the formula becomes: P = 480 * (1 + 0.112)^5.
Solving this equation, the bacterial population after 5 hours would be approximately 947.1 bacteria.
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Two
None
Infinitely many
Answer:
Option 1 - One
Step-by-step explanation:
Given : Equation
To find : How many solutions does the equation have?
Solution :
Step 1 - Write the equation,
Step 2 - Add 8 both side,
Step 3 - Solve the like terms
Therefore, The solution of the equation is only one as it is linear equation and the solution is at p=9.
So, Option 1 is correct.
Answer:
Answer:
Option 1 - One
Step-by-step explanation:
Given : Equation
To find : How many solutions does the equation have?
Solution :
Step 1 - Write the equation,
Step 2 - Add 8 both side,
Step 3 - Solve the like terms
Therefore, The solution of the equation is only one as it is linear equation and the solution is at p=9.
So, Option 1 is correct.
Step-by-step explanation:
Select the correct answer.
Which expression is equivalent to the given expression?
(12g^2h^7)(3g–^2h-4)
A. 36gh^3
B. 36h^3
C. 36/g^4h^28
D. 38/h^3
Answer:
C
Step-by-step explanation:
Answer:
its C
Step-by-step explanation:
Answer:
200 miles over 5 inches = 50 miles over x inches
200/5 = 50/x = 200x/250 =
x = 250/200 = 1.25
1.25 inches = 50 miles