How do you graph and work problem x+4y=16??

Answers

Answer 1

Answer: You have to give values to x or y to create points which can be represented on a system of axis. For example, for x=0 we would get 4y=16, so y=4 => A(0, 4). For y = 0 we would get x=16, so B(16, 0). I attached the graph

Answer 2

Answer:

Answer: x = 4

Step-by-step explanation:

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4. (02.06 MC)A cylinder and a cone have the same diameter: 8 inches. The height of the cylinder is 3 inches. The height of the cone is 18 inches.
Usen 3.14
What is the relationship between the volume of this cylinder and this cone? Explain your answer by determining the volume of each and comparing them. Show all your work. (10 points)

Answers

Answer: See explanation

Step-by-step explanation:

Diameter = 8 inches

Radius = Diameter/2 = 8/2 = 4 inches

Height of the cylinder = 3 inches

Height of the cone = 18 inches

Volume of a cylinder = π r² h

= 3.14 × 4² × 3

= 3.14 × 16 × 3

= 150.72

Volume of a cone = 1/3 π r² h

= 1/3 × 3.14 × 4² × 18

= 1/3 × 3.14 × 16 × 18

= 301.44

From the answer gotten, we can deduce that the volume of the cone is twice the volume of the cylinder.

37. A company is choosing between two tanks for mixing chemicals Bothhave the same price, so the company plans to choose the one thatcan holdtanksthemost chemicals. The first tank conical with a diameter of 10 feet anda heightof 15 feet. The second tank is a hemisphere with a radius of 5.5 feetOne cubic foot 7.48 gallons

Answers

Volume of the conical tank = 1/3pi*r^2 * h = 1/3pi * (10/2)^2 * 15 = 125pi cubic feet or 392.7 cubic feet = 392.7 * 7.48 gallons = 2937 gallons.

Volume of the hemispherical tank = 2/3pi * r^3 = 2/3pi * (5.5)^3 = 348.5 cubic feet = 348.5 * 7.8 gallons = 2606 gallons

Hence the conical tank will contain more chemicals

Given:
1st tank: conical with diameter of 10 feet and height of 15 feet.
2nd tank: hemisphere with a radius of 5.5 feet

volume of a cone = πr² h/3
V = 3.14 * (5ft)² * 15ft/3
V = 3.14 * 25ft² * 5ft
V = 392.5 ft³

392.5 ft³ * 7.48 gallons/ft³ = 2,935.9 gallons

volume of a hemisphere = (2πr³)/3
V = [2 * 3.14 * (5.5ft)³]/3
V = (2 * 3.14 * 166.375 ft³)/3
V = 1,044.835 ft³/3
V = 348.28 ft³

348.28 ft³ * 7.48 gallons/ft³ = 2,605.13 gallons

Natural numbers are part of every other category of numbers except?

Answers

Natural numbers are not part of irrational numbers: numbers which can't be described as a fraction of two rational numbers (pi is irrational! and so is e, another number used often in mathematics. )

Ise the diagram at the right to find the acute angle measure of the hands of a clock at the time 2:20

Answers

The question is about clock hands. The acute angle measure of the hands of a clock at the time 2:20 is 80 degrees.

Clock hands are essential components of analog clocks and watches, indicating the time by their positions. Typically, a clock has three hands: the hour hand, the minute hand, and the second hand. The hour hand is shorter and denotes the hours, while the longer minute hand points to the minutes. The second hand, the thinnest and longest, measures seconds. Clock hands move in a clockwise direction, and their synchronized motion helps people tell time at a glance, making them fundamental features of timekeeping devices for centuries.

To find the acute angle measure of the hands of a clock at the time 2:20, we need to determine the angle covered by the hour hand. In going from 12 to 3, the hour hand covers 1/4 of the 12 hours needed to make a complete revolution. Therefore, the angle between the hour hand at 12 and at 3 is 90 degrees. Since it is 20 minutes past 2, the minute hand will be 1/3 of the way between 2 and 3. This means the minute hand will be at an angle of 1/3 x 30 degrees = 10 degrees. The acute angle between the hour and minute hands can be found by subtracting the smaller angle from the larger angle. So, the acute angle measure of the hands of the clock at the time 2:20 is 90 degrees - 10 degrees = 80 degrees.

Learn more about clock hands here:

brainly.com/question/34460003

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Answer:

50 degrees

Step-by-step explanation:

To find the acute angle measure between the hour and minute hands of a clock at 2:20, you can use the following method:

First, calculate the minute hand's position:

The minute hand moves 360 degrees in 60 minutes, so in 20 minutes, it covers (20/60) * 360 = 120 degrees.

Next, calculate the hour hand's position:

The hour hand moves 360 degrees in 12 hours, so in 2 hours and 20 minutes, it covers (2 + 20/60) * (360/12) = (2 + 1/3) * 30 = (7/3) * 30 = 70 degrees.

Now, find the acute angle between the hour and minute hands:

Subtract the hour hand position from the minute hand position:

120 degrees (minute hand) - 70 degrees (hour hand) = 50 degrees.

So, the acute angle measure between the hands of the clock at 2:20 is 50 degrees.

What is the value of the expression below when w = 5?
2w2 – 2w + 3