Solve for X
2/3 x +10/60 =100/60

Answers

Answer 1
Answer:

Answer:

2 1/4

Step-by-step explanation:

subtract 10/60 from each side to get:

2/3x = 90/60

multiply each side by 3/2 to get:

x = 270/120

x = 27/12 or 2 1/4


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Answers

Answer:

226.08

Step-by-step explanation:

im pretty sure

In determining automobile-mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 33 mpg and a standard deviation of 1.7 mpg. Find the following:__________. a. P(X<30)
b. P(28c. P(X>35)
d. P(X>31)
e. the mileage rating that the upper 5% of cars achieve.

Answers

The upper 5% of cars have a mileage rating of 35.805 mpg

What is z score?

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean) / standard deviation

Given;  mean of 33 mpg and a standard deviation of 1.7

a) For < 30:

z = (30 - 33)/1.7 = -1.76

P(x < 30) = P(z < -1.76) = 1 - 0.8413 = 0.0392

b) For < 28:

z = (28 - 33)/1.7 = -2.94

P(x < 28) = P(z < -2.94) = 0.0016

c) For > 35:

z = (35 - 33)/1.7 = 1.18

P(x > 35) = P(z > 1.18) = 1 - P(z < 1.18) = 1 - 0.8810 = 0.119

d) For > 31:

z = (31 - 33)/1.7 = -1.18

P(x > 31) = P(z > -1.18) = 1 - P(z < -1.18) = 0.8810

e) The  upper 5% of cars achieve have a z score of 1.65, hence:

1.65 = (x - 33)/1.7

x = 35.805 mpg

The upper 5% of cars have a mileage rating of 35.805 mpg

Find out more on z score at: brainly.com/question/25638875

Answer:

a) P(X < 30) = 0.0392.

b) P(28 < X < 32) = 0.2760

c) P(X > 35) = 0.1190

d) P(X > 31) = 0.8810

e) At least 35.7965 mpg

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 33, \sigma = 1.7

a. P(X<30)

This is the pvalue of Z when X = 30. So

Z = (X - \mu)/(\sigma)

Z = (30 - 33)/(1.7)

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

Then

P(X < 30) = 0.0392.

b) P(28 < X < 32)

This is the pvalue of Z when X = 32 subtracted by the pvalue of Z when X = 28. So

X = 32

Z = (X - \mu)/(\sigma)

Z = (32 - 33)/(1.7)

Z = -0.59

Z = -0.59 has a pvalue of 0.2776.

X = 28

Z = (X - \mu)/(\sigma)

Z = (28 - 33)/(1.7)

Z = -2.94

Z = -2.94 has a pvalue of 0.0016.

0.2776 - 0.0016 = 0.2760.

So

P(28 < X < 32) = 0.2760

c) P(X>35)

This is 1 subtracted by the pvalue of Z when X = 35. So

Z = (X - \mu)/(\sigma)

Z = (35 - 33)/(1.7)

Z = 1.18

Z = 1.18 has a pvalue of 0.8810.

1 - 0.8810 = 0.1190

So

P(X > 35) = 0.1190

d. P(X>31)

This is 1 subtracted by the pvalue of Z when X = 31. So

Z = (X - \mu)/(\sigma)

Z = (31 - 33)/(1.7)

Z = -1.18

Z = -1.18 has a pvalue of 0.1190.

1 - 0.1190 = 0.8810

So

P(X > 31) = 0.8810

e. the mileage rating that the upper 5% of cars achieve.

At least the 95th percentile.

The 95th percentile is X when Z has a pvalue of 0.95. So it is X when Z = 1.645. Then

Z = (X - \mu)/(\sigma)

1.645 = (X - 33)/(1.7)

X - 33 = 1.645*1.7

X = 35.7965

At least 35.7965 mpg

From 12 teachers to 48 teachers using perecent

Answers

Answer:

Teachers increase = 300 %

Step-by-step explanation:

Method to increase or decrease:

Change= Actual - Original

Actual= 48

Original= 12

Change= 48-12= 36

P= (Change)/(Original) * 100

P= (36)/(12) * 100%

P= 3 * 100%

P= 300%

Reece is setting up a large fish tank. The tank is 1.8metres long and 0.6 metres wide. The water in the tank is 50 cm deep. Reece needs to add a liquid treatment to the water. The instructions tell him to add 5 ml of treatment for every 0.18 m3. How many treatment does Reece need to add?​

Answers

Reece needs to add 3 treatments to the fish tank.

How to determine How many treatment does Reece need to add

First, we need to calculate the volume of the fish tank in cubic meters.

Volume = Length × Width × Depth

Volume = 1.8 m × 0.6 m × 0.5 m (converting 50 cm to meters by dividing by 100)

Volume = 0.54 m³

Now, we can calculate how many treatments Reece needs to add using the given ratio of 5 ml per 0.18 m³.

Number of treatments = Volume of tank / Volume per treatment

Number of treatments = 0.54 m³ / 0.18 m³

Number of treatments = 3 treatments

Therefore, Reece needs to add 3 treatments to the fish tank.

Learn more about the volume at brainly.com/question/463363

#SPJ3

Answer:

15 ml

Step-by-step explanation:

Find the volume of the tank which is 1.8m*0.6m*0.5m=0.54m^3

For every 0.18m^3,5ml of treatment is added,what of 0.54m^3

(0.54m^3*5ml)/(0 18m^3)=15ml

7th grade math help me plzzz

Answers

Answer:

a. -7 + 3

b. draw 7 negatives + 7 positives

Step-by-step explanation:

Answer:

3.a) -7 + 3

3.b) 4

I hope this helps!

Hey can you please help me posted picture of question

Answers

The correct option is (B)16x^2 + 8x + 1

Explanation:
Add all the boxes:
There are 16 (x^2) boxes;
There are 8 (x) boxes;
And the constants = 1

So it becomes:
16x^2 + 8x + 1

And the product is (4x+1)(4x+1)
4x(4x+1) + 1(4x+1)
16x^2 + 4x + 4x + 1
16x^2 + 8x + 1 (Same)