A researcher is interested in testing the perceived effort (PE) of runners under three different terrains. PE is measured on a scale that ranges from 0 to 15, where higher scores indicate greater effort. The three terrains were a running track (i.e. the control), a mostly flat sidewalk, and a hilly neighborhood. Participants were randomly assigned to only one type of terrain. What type of analysis should the researcher conduct

Answers

Answer 1

Answer: I don’t know i’m only in eighth grade

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A person's blood pressure is monitored by taking 8 readings daily. The probability distribution of his reading had a mean of 129 and a standard deviation of 7. a. Each observation behaves as a random sample. Find the mean and the standard deviation of the sampling distribution of the sample mean for the eight observations each day. b. Suppose that the probability distribution of his blood pressure reading is normal. What is the shape of the sampling distribution? c. Refer to (b). Find the probability that the sample mean exceeds 140.

The American Community Survey is an ongoing survey that provides data every year to give communities the current information they need to plan investments and services. The 2010 American Community Survey estimates that 14.6% of Americans live below the poverty line, 20.7% speak a language other than English (foreign language) at home, and 4.2% fall into both categories. a. Draw a Venn diagram summarizing the variables and their associated probabilities
b. What percent of Americans live below the poverty line and only speak English at home?
c. What percent of Americans live below the poverty line or speak a foreign language at home?

Answers

Answer:

b. 10.4

c. 26.9

Step-by-step explanation:

Let the universal set U = 100% which is the total no of people in the American community

Let A = 14.6% which is the total no of people living below poverty line

Let B = 20.7% which is the total no of people speaking foreign Language

C = 4.2% no of people who both speak foreign language and live below poverty line

X = no of people who neither live below poverty line nor speak foreign language

P (A) = 14.6%

P (B) = 20.7%

P (C) = P (A ∩ B) = 4.2%

P (A – C) = P (A ∩ U) = 14.6 – 4.2 = 10.4%

P (B – C) = P (B ∩ U) = 20.7 – 4.2 = 16.5%

P (X) = P (A ᴜ B) c =100 – (10.4 + 4.2 + 16.5) = 68.9%

a. The venn diagram is as shown above

b. Percent of Americans who live below poverty line and Speak English at home(minus foreign lang speakers living below poverty line) that is A only

= A – C

= 14.6 – 4.2

= 10.4%

c. Percentage of Americans Living below poverty line or Speaking foreign language

= A only + B only

A only = A – C ( People living below poverty line only)

= 14.6 -4.2

= 10.4%

B only = B – C ( people speaking foreign languages only)

= 20.7 – 4.2

= 16.5%

Hence

A only + B only = 10.4 + 16.5 = 26.9%

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Answers

Answer:

y = 3x + 3

Step-by-step explanation:

y = mx + b

m = slope

m = y2-y1/x2-x1 = 9-6/2-1 = 3/1 = 3

m = 3

b = y-intercept

b = 3

Answer:

The answer would be y = 3x + 3.

Step-by-step explanation:

how can you determine that the polynomial function does not have any zeros with even Multiplicity? Explain.

Answers

Answer:

See Below.

Step-by-step explanation:

Remember multiplicity rules:

If a factor has an odd multiplicity (e.g. 1, 3, 5...), then the graph will cross the x-axis at that point.

If a factor has an even multiplicity (e.g. 2, 4, 6...), then the graph will bounce off the x-axis at that point.

From the graph, we can see that at our zeros, the graph always passes through the x-axis.

Hence, we do not have any zeros with even multiplicity since the graph does not "bounce" at any of the zeros.

Final answer:

To determine if a polynomial function has zeros with even multiplicity, examine the graph or the exponents of the factors in the function. If there are no real zeros or all the factors are raised to odd powers, there won't be any even multiplicity zeros.

Explanation:

In order to determine if a polynomial function has zeros with even multiplicity, we can examine the function's graph. If a polynomial function does not have any real zeros, then it does not have any zeros with even multiplicity. This is because even multiplicity zeros occur when a factor appears multiple times in the function. However, if all the factors are raised to odd powers, then there won't be any even multiplicity zeros. On the other hand, if the function does have real zeros, we can look at the graph of the function to check if any zeros occur with even multiplicity.

Learn more about Determining zeros of polynomial functions here:

brainly.com/question/11284559

#SPJ11

What does the line y=5 represent in X=8(y-5)^2+2

Answers

Answer:

The right answer is vertex

Gabrielle is 10 years older than mike. the sum of their ages is 56. how old is mike

Answers

Answer: 23

Step-by-step explanation:

Let

�

m be Mike's age.

According to the given information, Gabrielle is

�

m+10 years old.

The sum of their ages is given by:

�

(

�

)

m+(m+10)=56

Combining like terms, we get:

�

2m+10=56

Subtracting 10 from both sides, we have:

�

2m=46

Dividing both sides by 2, we get:

�

m=23

So, Mike is 23 years old.

mike is 23 years old

) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station

Answers

Complete Question

The probability that a single radar station will detect an enemy plane is 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane? (Round your answer to one decimal place.)

Answer:

$n \approx 4$

Step-by-step explanation:

From the question we are told that

The probability that a single radar station will detect an enemy plane is $p =0.65$

Gnerally the probability that an enemy plane flying over will be detected by at least one station is mathematically represented as

$P(X \ge 1 ) = 0.98$

=> $P(X \ge 1 ) = 1 - P(X < 1) = 0.98$

=> $P(X = 0) = 1 - 0.98$ Note $P(X < 1) = P(X = 0)$

=> $P(X = 0) = 1 - 0.98$

=> $P(X = 0) = 0.02$

Generally from binomial probability distribution function

$P(X = 0) = ^nC_0 * p^(0) * (1- p)^(n- 0)$

Here C represents combination hence we will be making use of of combination functionality in our calculators

Generally any number combination 0 is 1

$P(X = 1) = 1 * 1* (1- 0.65)^(n- 0) = 0.02$

=> $(1- 0.65)^(n- 1) = 0.02$

taking log of both sides

$log [(0.35)^(n- 1) ] = log (0.02)$

=> ${n- 1}log[0.35] = -1.699$

=> ${n- 1}* -0.4559 = -1.699$

=> $n= 3.7264 + 1$

=> $n= 4.7264$

=> $n \approx 4$

Gnerally the expected number of stations that will detect an enemy plane is

$E(X) = 7 * 0.65$

=> $E(X) \approx4.5$

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