Which most likely would be a new social issue resulting from the installation of a dam? A. Antibiotic resistance

B. Habitat destruction

C. Greater exposure to radiation

D. Increase in biodiversity

Answers

Answer 1
Answer: C. Greater exposure to radiation


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The heat of combustion of propane, C3H8, is 2220 kJ/mol. The specific heat of copper is 0.385 J/g°C. How many grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C, assuming none of the heat is lost to the surroundings?

Answers

The heat of combustion (\DeltaHc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions.

3.05988g. grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C.

What is meant by heat of combustion?

  • The heat of combustion (\DeltaHc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions. In most cases, a hydrocarbon reacts with oxygen to produce carbon dioxide, water, and heat.
  • The heat of combustion of a substance is the amount of energy released when a specific amount (e.g., 1 mol, 1g, 1 L) of the substance completely burns in oxygen. The heat of combustion is typically measured at 298K (25 C) and 101.3kPa.
  • The energy released when a substance X completely burns with an excess of oxygen under standard conditions (25°C and 1 bar). It is the inverse of the enthalpy change for the combustion reaction in thermodynamic terms.

q=m*c*(change of T)

q=10000g(0.385J/g*c)*(65.0C-25.0C)or (338.2 K-298.2K)

q=154000J

154000J*(1 mol/2220 KJ)=69.36936 x 10 ^-3 mol

here's where I'm stuck

0.069369 mol

and i know that for every 1 mol there is 44.11g of C3H8.

0.069369 mol* (44.11g C3H8)/1mol = 3.05988g.

To learn more about : Heat of combustion

Ref : brainly.com/question/25109613

#SPJ2

Answer:

Explanation:

q = (mass) (temp change) (specific heat)

q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ

154 kJ / 2220 kJ/mol = 0.069369369 mol

0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)

answer choice 4

Who developed a way of showing valence electrons?

Answers

American chemist Gilbert N. Lewis developeda way of showing valence electrons.
Gilbert N. Lewis was the scientist who developed a way of showing valence electrons.
:D

Elements can be described by their properties. Some of these properties are physical properties and some are chemical properties Observe the list provided. Which one of these contains ONLY Cchemical properties A) C,E,F
B) B,C,E
C) B, E, F
D) C,D,E​

Answers

Flammability, Ability to rust and Ability to tarnish (C,E,F) are chemical properties of an element.

The property of an element is the characteristic feature of that element which helps us to differentiate it from another  element.

We have

  • The Physical proprieties- These are features of an element which we can identify by sight and touch, Some of them include colour, hardness, boiling and ,melting point, size etc
  • Chemical properties These are the features of an element which w\e observe when the element has undergone a chemical change which changes its composition. Examples are Flammability, rust, tarnish , corrosion etc.

See more here:brainly.com/question/2116116

Its a c,e,f

Sadly i got it wrong

Which question would most likely be studied by a physicist?A. Were there ever any living organisms on Mars?
B. How can the forces on a space probe be controlled so it will land
on Mars?
O C. What type of substances make up the soil on Mars?
O D. Should the government spend taxpayers' money to send space
probes to Mars?

Answers

Answer:A

Explanation: Were there any living organisms is the answer because physics is the study of matter,its motion and behaviour of space and time and some other topics like energy and force.

Answer:

B

Explanation:

Forces and vectors on a probe are a physics thing

What type of orbital is designated by the quantum numbers n = 3, l = 0 ?

Answers

Answer:

The quantum numbers n = 3 and l = 0 correspond to a specific type of orbital within the third principal energy level (n = 3) of an atom.

When l = 0, it corresponds to the s orbital. So, the orbital designated by the quantum numbers n = 3, l = 0 is the 3s orbital. The 3s orbital is spherically symmetrical and has a single orientation within its energy level.

What two factors determine the thermal energy in a substance

Answers

the answer to that is mass and chemical