The heat of combustion (Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions.
3.05988g. grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C.
q=m*c*(change of T)
q=10000g(0.385J/g*c)*(65.0C-25.0C)or (338.2 K-298.2K)
q=154000J
154000J*(1 mol/2220 KJ)=69.36936 x mol
here's where I'm stuck
0.069369 mol
and i know that for every 1 mol there is 44.11g of C3H8.
0.069369 mol* (44.11g C3H8)/1mol = 3.05988g.
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Answer:
Explanation:
q = (mass) (temp change) (specific heat)
q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ
154 kJ / 2220 kJ/mol = 0.069369369 mol
0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)
answer choice 4
B) B,C,E
C) B, E, F
D) C,D,E
Flammability, Ability to rust and Ability to tarnish (C,E,F) are chemical properties of an element.
The property of an element is the characteristic feature of that element which helps us to differentiate it from another element.
We have
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Its a c,e,f
Sadly i got it wrong
B. How can the forces on a space probe be controlled so it will land
on Mars?
O C. What type of substances make up the soil on Mars?
O D. Should the government spend taxpayers' money to send space
probes to Mars?
Answer:A
Explanation: Were there any living organisms is the answer because physics is the study of matter,its motion and behaviour of space and time and some other topics like energy and force.
Answer:
B
Explanation:
Forces and vectors on a probe are a physics thing
Answer:
The quantum numbers n = 3 and l = 0 correspond to a specific type of orbital within the third principal energy level (n = 3) of an atom.
When l = 0, it corresponds to the s orbital. So, the orbital designated by the quantum numbers n = 3, l = 0 is the 3s orbital. The 3s orbital is spherically symmetrical and has a single orientation within its energy level.