If you run a mile in 12 min how fast were you going

Answers

Answer 1

Answer: You would have been running 5 mph.

Related Questions

The height of a trapezoid is 8 ft and its area is 116 ft2. One base of the trapezoid is 1 ft shorter than twice the length of the other base. Find the length of each base.
Which expression is equivalent to 10 - 810−810, minus, 8?
Which of the following exponential functions goes through the points (1, 12) and (2, 36)?f(x) = 4(3)−xf(x) = 3(4)−xf(x) = 3(4)xf(x) = 4(3)x
Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenths place.
3.3x10^5+44,000 in scientific notation? please please

Paul picked and bagged a total of 30 pounds of apples on Saturday and Sunday. He filled each bag with 5 pounds of apples. On Saturday, Paul filled 2 bags with apples. How many bags did Paul fill with apples on Sunday? Complete and solve the equation to show how many bags Paul filled with apples on Sunday.

Answers

Answer:

Paul filled 4 bags on Sunday.

Step-by-step explanation:

Since each bag that was filled weighed 5 pounds then we can use the following equation to solve for the amount of bags, where (x) is the number of bags filled on Saturday and (y) is the number of bags filled on Sunday.

5x + 5y = 30

Now since we are told that on Saturday Paul filled 2 bags then we would only be left with the variable y (number of bags filled on Sunday). We can solve for y

5(2) + 5y = 30

10 + 5y = 30 ... subtract 10 on both sides

5y = 20 ... divide by 5 on both sides

y = 4

Finally, we can see that Paul filled 4 bags on Sunday.

A surveyor measures the angle of elevation to the top of a building to be 70 degrees. The surveyor then walks 50 ft farther from the base of the tower and measures the angle of elevation to be 50 degrees. The surveyor's angle-measuring device 5.5 ft from the ground. How tall is the building, to the nearest foot?

Answers

Answer:

height of building,H = 5.5 ft + 105.2 ft = 111 ft to the nearest ft.

Step-by-step explanation:

in this question we have given angle of elevation= $70^o$

when surveyor walks 50m farther from the base of the tower that time angle of elevation= $50^o$

As shown in figure in triangle ABD

$Tan (70)= (h)/(x)$ .............(1)

or h=2.74x

and in triangle ABC

$Tan (50)= (h)/(50+x)$ ...........(2)

put value of h in equation 2

we got,

$1.19= (2.74x)/(50+x)$

$(50+x)1.19=2.74x\n50* 1.19+1.19x-2.74x=0\n59.5-1.55x=0\n59.5=1.55x\nx=38.39ft$

therefore,

Height of the tower is,h=2.74\times 38.39ft

h=105.2ft

Therefore,

height of building,H = 5.5 ft + 105.2 ft = 111 ft to the nearest ft.

43.804 ft

Working;
Start by drawing the diagram as shown in the attached diagram;
Then use the following trigonometric relations;
Tan (50)= $(h)/(50+x)$
Tan (70)= $(h)/(x)$

You can then use the value of x to find the value of h. Then add 5.5 ft to h to get height of the building

What is 20% of $40.00 please help

Answers

Seriously ? 8$ :) - doesn't your Smarthphone have a Calculator function?

Correct answer 8$

Answer:

Step-by-step explanation:

How to answer this question???
thanks

Answers

$(2m)/(5)+3=7(4m-3)\ \ \ \ |use\ distributive\ property:a(b-c)=ab-ac\n\n(2m)/(5)+3=28m-21\ \ \ \ \ |multiply\ both\ sides\ by\ 5\n\n2m+15=140m-105\ \ \ \ |subtract\ 140m\ from\ both\ sides\n\n-138m+15=-105\ \ \ \ |subtract\ 15\ from\ both\ sides\n\n-138m=-120\ \ \ \ |divide\ both\ sides\ by\ (-138)\n\nm=(120:6)/(138:6)\n\n\boxed{m=(20)/(23)}$

If 4 (log3 1/27)=X what is the value of X