Emily and Sara had a total of $80.after Sara spent 1/3 of her money and Emily spent $17,Emily had twice as much money as Sarah.how much money did Emily have then Sara at first?

Answers

Answer 1
Answer: x/3-17=80
x/3=97
x=291

291-97=194

194-97=97

Emily had $97 more than Sara.

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A: 2x - 3y = 6B: 3x - 2y = -9C:y=-x-5D:y= {x2Which lines are parallel?A)A and cB)B and CB and DD)A and D
ohn and 3 friends are going out for pizza for lunch. They split one pizza and 4 large drinks. The pizza cost $13.00. After using a $6.00 gift certificate, they spend a total of $13.20. Write an equation to model this situation, and find the cost of one large drink.
a football is selling for 35% off the original price. the original price was $60. what is the sale price of the football.
Solve the equation for x: 2(8x – 16) = 48

An auto repair shop charged $75/h for labor plus an additional $89 for parts. If the shop worked for 2 h, which equation represents the total repair cost C ?A. C = 75(2) − 89
B. C = 89(2) + 75
C. C = 75 + 89
D. C = 75(2) + 89

Answers

Answer:

The total cost for the repair  is represented by C = 75 (2) + 89 .

Option (D) is correct .

Step-by-step explanation:

As given

An auto repair shop charged $75/h  for labor plus an additional $89 for parts.

If the shop worked for 2 h.

C = Represented the total repair cost .

Than the equation becomes

C = 75 × 2 + 89

C = 75 (2) + 89

Therefore the total cost for the repair  is represented by C = 75 (2) + 89 .

Option (D) is correct .

d. C= 75(2)+89 because you multiply the amount of hours by the cost per hour then add the cost of parts

Answer please it’s a big exam

Answers

Answer:

Solve for be is 56

Step-by-step explanation:

That the answer

The answer to this question is 56

Solve by factoring. x2 - 49 = 0

Answers

The solution to the given quadratic equation buy factoring is: x = -7 or 7

How to solve quadratic equations?

A quadratic equation is an equation of degree 2 and has the standard form: ax² + bx + c = 0, with a ≠ 0

We can solve quadratic equations by:

- Completing the square

- Quadratic formula

- Factoring

We are given the quadratic equation as:

x² - 49 = 0

Factoring this gives us:

(x + 7)(x - 7) = 0

Thus:

x - 7 = 0 or x + 7 = 0

x = -7 or 7

Read more about quadratic equations at: brainly.com/question/1214333

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Answer:

Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0

Step-by-step explanation:

Solve by factoring.

x2 - 49 = 0Solve by factoring.

x2 - 49 = 0

-5(-6k + 10) =
Help ASAP

Answers

Answer:

30k - 50

Step-by-step explanation:

-5 (-6k + 10)

= 30k - 50

Divide 7/15 by 3/5.
A. 75/21
B. 7/9
C. 7/25
D. 21/75

Answers

In this question there is nothing complicated. Only thing is to know the way fractions can be divided. Once that is known the problem would be one of the easiest to solve. Now let us get back to the problem and look at all the information's that are given in the question.
Divide 7/15 by 3/5 = (7/15)/(3/5)
                              = (7 * 5)/(15 * 3)
                               = (35/45)
Dividing the numerator and the denominator by 5 for simplifying purpose, we get
                               = 7/9
So from the above deduction we can easily conclude that 7/9 is the correct answer and option "B" is the correct option among all the options given in the question.
If you would like to solve 7/15 / 3/5, you can calculate this using the following steps:

7/15 / 3/5 = 7/15 * 5/3 = 7/9

The correct result would be B. 7/9.

What is the end behavior of the graph of the polynomial function f(x) = –x^5 + 9x^4 – 18x^3?

Answers

Answer: its C

Step-by-step explanation:

hello

For example, the monomial y = x 2 has the following end behavior: y → ∞ as x → −∞ and y → ∞ as x → ∞ 
For any polynomial, the end behavior is determined by the term that contains the highest power of x, because when x is large, the other terms are relatively insignificant in size.