A hot air balloon descends to the ground. The function h(t) = 210 – 15t can be used to describe the altitude of the balloon as it approaches the ground. Which statement best describes the graph of the function that models the descent of the balloon?A) The graph is discrete because there cannot be fractional values for time.
B) The graph is discrete because there cannot be negative values for altitude.
C) The graph is continuous because there can be fractional values for time.
D) The graph is continuous because there can be negative values for altitude.

Answers

Answer 1
Answer:

Answer:

Option c

Step-by-step explanation:

Given that a hot air balloon descends to the ground.

The function

h(t) = 210 - 15t

can be used to describe the altitude of the balloon as it approaches the ground.

Here t = time and h = height

Since t cannot be negative we can t starting from 0

t can take any fractional value and h is well defined for any value of t positive

So option c is right

Answer 2
Answer: C The graph is continuous because there can be fractional values for time

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(-3l^2w^3)(2lw^4) simplify express using exponents.

Answers

The simplified algebraic expression using exponents is (-3l^2w^3)(2lw^4) simplifies to -6l^3w^7.

To simplify the given expression using exponents, follow these steps:

Multiply Coefficients: Multiply the coefficients (-3) and (2) to get -6.

Combine Like Bases: For the variables with the same base (l and w), add the exponents when they are multiplied together.

Here, l^2 * l^1 = l^(2+1) = l^3, and w^3 * w^4 = w^(3+4) = w^7.

Final Simplified Expression: Combine the results from steps 1 and 2 to get -6l^3w^7.

Therefore, the simplified expression using exponents is (-3l^2w^3)(2lw^4) simplifies to -6l^3w^7.The expression has been simplified using the rules of exponentiation. This simplification helps in reducing the complexity of the expression and making calculations easier.

Learn more about algebraic expression here:

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Answer:

Step-by-step explanation:

(-3)(2)= -6

(l^2w^3)(lw^4) = l^3w^7

-6l^3w^7

What is the slope of the line that passes through (37, -9) and (36, 81)

Answers

Answer:

m= -90 is your answer

Step-by-step explanation:

For future reference, you should try using Symbolab, it works really well and I use it ALL the time!

Lily used 6 loaves of bread on a 7 day camping trip. How many loaves of bread will she use on her next camping trip that will last for 21 days? ​

Answers

Answer:

18

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

If six loaves lasted seven days, and she is going for 21 days next time, that is three times the amount of days she went on her last camping trip. so you multiply the amount of loaves by 3.

Find the general solution of the following equation. Express the solution explicitly as a function of the independent variable. x^2 dw/dx = √ w(2x+5)

Answers

Answer:

Therefore the general solution is

2 \sqrt w = 2 ln(x) - 5 \frac1x +c

Step-by-step explanation:

Integration Rule:

  1. \int x^n dx= (x^(n+1))/(n+1)+c
  2. \int \frac1x dx= ln(x) +c

Given differential equation is

x^2 (dw)/(dx)= √(w)(2x+5)

\Rightarrow x^2 dw= √(w) (2x+5) dx    [ multiplying dx both sides]

\Rightarrow (dw)/(\sqrt w)= ((2x+5))/(x^2) dx                [ dividing x^2\sqrt w both sides]

Integrating both sides

\int (dw)/(\sqrt w)=\int ((2x+5))/(x^2) dx

\Rightarrow \int w^(-\frac12) dw=\int ((2x)/(x^2)+(5)/(x^2) )dx

\Rightarrow \int w^(-\frac12) dw=\int (2)/(x)dx +\int(5)/(x^2) dx

\Rightarrow (w^(-\frac12+1))/(-\frac12+1) =2ln x+5 (x^(-2+1))/(-2+1)+c   [ c is arbitrary constant]

\Rightarrow 2 \sqrt w = 2 ln(x) - 5 \frac1x +c

Therefore the general solution is

2 \sqrt w = 2 ln(x) - 5 \frac1x +c

Which expression is equivalent to (m2p–2r7)(m–5p4r2)?

Answers

Answer:

=(m2p+−2r7)(m+−5p4r2)

=(m2p)(m)+(m2p)(−5p4r2)+(−2r7)(m)+(−2r7)(−5p4r2)

=m3p−5m2p5r2−2mr7+10p4r9

=10p4r9−5m2p5r2−2mr7+m3p

Step-by-step explanation:

:D

Which statement best describes the areas and perimeters of the figures below?

Answers

Answer:

They have different areas and different perimeters