Compute the amount of interest earned in the following simple interest problem.A deposit of $1,600 at 6% for 180 days:

Answers

Answer 1
Answer: with 6% is 1,696. for 180 days, $305,280 
Answer 2
Answer: I=PRT
I=interest
P=principal
R=rate in decimal
T=time in yaers

365 days per year
t=180/365

given
P=1600
R=6%=0.06
T=180/365

I=1600*0.06*180/365
I=96*180/365
I=47.342

rounds to
Interst=$47.34

Related Questions

Please help me with this!!Thank u
If a coin is flipped 75 times, in how many ways could there be exactly two tails?
The area, A, of a square is equivalent to the square of its side lengths. choose more than one!1::: A = (6)(6) square units2::: A = s2 square units3::: A = (x)(x) square units4::: A = (x+x) square units5::: A = 2(6) square units
Solve the system of equations.5x + y = 93x + 2y = 4 A) (-2, 5) B) (1, 4) C) (2, -1)D) (4, -4)
Lena is making two dishes for an event. Each batch of her mac-n-cheese recipe calls for 6 ounces of cheese and 2 tablespoons of basil. For every two pizzas, she needs 16 ounces of cheese and 5 tablespoons of basil. Part A) Lena buys a 32-oz package of cheese. Does she have enough cheese to make 2 batches of man-n-cheese and 3 pizzas?

What is the nth term for 3,4.5,6,7.5

Answers

If nth means ninth then the answer is 15.  If nth is not ninth then tell me I am glad to help!

I need the answer as a radical :) u dont have to show work

Answers

Answer:

10

Step-by-step explanation:

Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length.A two column proof of the theorem is shown but the statement and reasons are not in correct order.

Answers

Reasons:
I) Segment DE is half the length of segment AC. By substitution

II) Segment DE is parallel to segment AC. Slopes of parallel lines are equal.

III) The coordinates of point D are (4, 5) and coordinates of point E are (5, 3) By the midpoint form

Given a test statistic of t=2.315 of a left tailed test with n=8

Answers

Answer:

Null hypothesis: \mu =110

Alternative hypothesis:\mu \neq 110

The sample size on this case is n=8, then the degrees of freedom are given by:

df = n-1= 8-1=7

The statistic is given by:

t= (\bar X -\mu)/((s)/(√(n)))

For this case the value of the statistic is given t = 2.315

Since we are using a bilateral test the p value would be given by:

p_v = 2*P(t_(7)>2.315) =0.054

And we can use the following excel code to find it:

"=2*(1-T.DIST(2.315;7;TRUE))"

Since the p value is higher than the significance level given we FAIL to reject the null hypothesis. And the best conclusion would be:

0.05<P-value <0.10, fail to reject the null hypothesis

Step-by-step explanation:

Assuming this complete question :"Given a test statistic of t=2.315 of a left-tailed test with n=8, use a 0.05 significance level to test a claim that the mean of a given population is equal to 110.

Find the range of values for the P-value and state the initial conclusion 1 point) 0.05<P-value <0.10; reject the null hypothesis

0.05<P-value <0.10, fail to reject the null hypothesis

0.025 < P-value <0.05; reject the null hypothesis

0.025< P-value<0.05; fail to reject the null hypothesis"

For this case they want to test if the population mean is 110 or no, the systemof hypothesis are:

Null hypothesis: \mu =110

Alternative hypothesis:\mu \neq 110

The sample size on this case is n=8, then the degrees of freedom are given by:

df = n-1= 8-1=7

The statistic is given by:

t= (\bar X -\mu)/((s)/(√(n)))

For this case the value of the statistic is given t = 2.315

Since we are using a bilateral test the p value would be given by:

p_v = 2*P(t_(7)>2.315) =0.054

And we can use the following excel code to find it:

"=2*(1-T.DIST(2.315;7;TRUE))"

Since the p value is higher than the significance level given we FAIL to reject the null hypothesis. And the best conclusion would be:

0.05<P-value <0.10, fail to reject the null hypothesis

What number needs to be added to both sides of the equation in order to complete the square?

Answers

To complete the square for the equation X^2 + 16X + __ = 18 + __, we need to add 64 to both sides to get the equation X^2 + 16X + 64 = 18 + 64.

To complete the square for the given quadratic equation, we need to add a specific value to both sides of the equation. That specific value is the square of half the coefficient of the X term. In this case, the X term's coefficient is 16, so we need to take half of 16 (which is 8) and square it (which is 64).

So, the number to be added to both sides of the equation is 64.

The completed square equation then becomes: X^2 + 16X + 64 = 18 + 64.

Learn more about Completing the square here:

brainly.com/question/4822356

#SPJ2

The probable question may be:

What number needs to be added to both sides of the equation in order to complete the square?

X^2+16X+____=18+___

Answer:

16

Step-by-step explanation:

Given x^2 + 16x = 18.  Complete the square:

Take half of the coefficient of x (in other words, take half of 16) and square the result:  we get 8^2 = 64.

Add 64, and then subtract 64 from x^2 + 16x   + 64                         = 18 + 64

Then (x + 8)^2  = 82.  From this point on it's easy to find the roots, but we were not asked to do so.  

The desired number is 64; note that it is (16/2)^2.

Which polynomial can be simplified to a difference of squares? 10a2 + 3a – 3a – 16 16a2 – 4a + 4a – 1 25a2 + 6a – 6a + 36 24a2 – 9a + 9a + 4

Answers

16a² - 4a + 4a - 1 can be simplified to a difference of squares:

16a² - 4a + 4a - 1 =
16a
² - 1 =
(4a)² - 1² = 
(4a-1)(4a+1)

Answer:

2.16a^2-4a+4a-1

Step-by-step explanation:

We have to find the polynomial can be simplified to a difference of squares.

1.10a^2+3a-3a-16

Combine like terms

10a^2-16

10 in 10a^2 is not a perfect square number  because when a number end with one zero then the number is not perfect square number.

Therefore, it can not be simplified to a difference of squares.

2.16a^2-4a+4a-1

16a^2-1

Combine like terms

(4a)^2-(1)^2

Hence, the polynomial can be simplified as difference of squares.

3.25a^2+6a-6a+36

Combine like terms

25a^2+36

(5a)^2+(6)^2

Hence, the polynomial can not be simplified as  difference of squares because the polynomial can be  simplified as sum of squares.

4.24a^2-9a+9a+4

Combine like terms

24a^2+4

24a^2+(2)^2

24=2* 2* 3* 2

24 is not  a perfect square number because  when factorize 24 then 2 and 3 are not paired.

Hence, the polynomial can not be simplified as difference of squares.