Answer: Doris was left with $4216.93.
Step-by-step explanation:
Since we have given that
Principal amount = $ 4000
Rate of interest = 6%
He put $4000 in a 5 year CD paying 6% interest compounded monthly.
After 2 years, she withdrew all her money.
so, Amount after 2 years when it is compounded annually.
As an early withdrawal penalty, she paid back all the interest she made during the first year.
Amount left with Doris is given by
Hence, Doris was left with $4216.93.
The volume generated by rotating the region in the first quadrant bounded by y = ex and the x-axis from x = 0 to x = ln(3) about the y-axis is (πln(3)3)/3.
To find the volume generated by rotating the region in the first quadrant bounded by y = ex and the x-axis from x = 0 to x = ln(3) about the y-axis, we can use the disk method. The disk method involves slicing the region into thin disks and adding up their volumes.
The volume of each disk is πr2h, where r is the radius of the disk and h is the thickness of the disk. In this case, the radius of each disk is x and the thickness is dx.
So, the volume of the region is:
V = ∫0ln(3)πx2dx
We can use the power rule for integration to solve this integral:
V = π∫0ln(3)x2dx = π[(x3)/3]0ln(3) = π[(ln(3)3)/3 - (03)/3] = (πln(3)3)/3
Therefore, the volume generated by rotating the region in the first quadrant bounded by y = ex and the x-axis from x = 0 to x = ln(3) about the y-axis is (πln(3)3)/3. This is the exact form of the volume.
To know more about disk method refer here:
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B. The graph would shift down 5 units.
C. The graph would shift up 5 units.
D. The graph would shift 5 units to the left.
Consider the function y=x^2+5x-2 . What would happen to the graph if (x + 5) was substituted in place of the x?
A. The graph would shift 5 units to the right.
B. The graph would shift down 5 units.
C. The graph would shift up 5 units.
D. The graph would shift 5 units to the left.
Option: D is the correct answer.
D. The graph would shift 5 units to the left.
We know that the transformation of a function f(x) to f(x+a) is a shift of the function either to the left or to the right by a units depending on the sign of a i.e. if a>0 then the shift is a units to the left
and if a<0 then the shift is a units to the right.
Here we have:
is converted to:
Here we have a=5>0
Hence, the shift is 5 units to the left.