for all of my study island friends the answer is D. all of these
Answer:
1.552 moles
Explanation:
First, we'll begin by writing a balanced equation for the reaction showing how C8H18 is burn in air to produce CO2.
This is illustrated below:
2C8H18 + 25O2 -> 16CO2 + 18H2O
Next, let us calculate the number of mole of C8H18 present in 22.1g of C8H18. This is illustrated below:
Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol
Mass of C8H18 = 22.1g
Mole of C8H18 =..?
Number of mole = Mass /Molar Mass
Mole of C8H18 = 22.1/144
Mole of C8H18 = 0.194 mole
From the balanced equation above,
2 moles of C8H18 produced 16 moles of CO2.
Therefore, 0.194 mole of C8H18 will produce = (0.194x16)/2 = 1.552 moles of CO2.
Therefore, 1.552 moles of CO2 are emitted into the atmosphere when 22.1 g C8H18 is burned
To calculate the number of moles of CO2 emitted into the atmosphere when 22.1 g of C8H18 is burned, we need to convert the mass of C8H18 to moles using its molar mass. The mole ratio between C8H18 and CO2 is 1:8 based on the balanced chemical equation. Thus the number of moles of CO2 produced can be calculated by multiplying the number of moles of C8H18 by the mole ratio.
To calculate the number of moles of CO2 emitted into the atmosphere when 22.1 g of C8H18 is burned, we need to convert the mass of C8H18 to moles using its molar mass. The molar mass of C8H18 is calculated by summing the atomic masses of its constituent elements: (12 g/mol for carbon)(8 carbon atoms) + (1 g/mol for hydrogen)(18 hydrogen atoms) = 114.22 g/mol for C8H18.
Next we need to use the balanced chemical equation for the combustion of C8H18 to determine the mole ratio between C8H18 and CO2. The balanced equation is: C8H18 + 12.5 O2 → 8 CO2 + 9 H2O.
From the balanced equation, we can see that 1 mole of C8H18 produces 8 moles of CO2. Thus we can calculate the number of moles of CO2 produced by dividing the mass of C8H18 by its molar mass and multiplying by the mole ratio:
number of moles of CO2 = (mass of C8H18 / molar mass of C8H18) * 8
#SPJ3
Fe2O3 + CO → Fe + CO2
B.
Fe2O3 + 3CO → 2Fe + 3CO2
C.
2Fe2O3 + 3CO → 2Fe + 3CO2
D.
3Fe2O3 + CO → 3Fe + 2CO2
Оа
Ob
Ос
0.39 moles
6405.00 moles
128.10 g
2.56 moles
Review Answers
Answer:
0.39 moles
Explanation:
To find how many moles are in 50.0 g of CaC₂O₄ you divide the grams of the sample by the molar mass of the compound;
=0.39 mol
The grams cancel out and you are left with moles!
I hope this help ^-^
Answer
its B
Explanation:
B.
Nuclear energy produces little air pollution.