Molarity = 0.1516 mol.L⁻¹
Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,
Molarity = Moles / Volume of Solution ----- (1)
Data Given;
Mass = 8.45 g
Volume = 0.750 L
Step 1: Calculate Moles for given mass as,
Moles = Mass / M.mass
Moles = 8.45 g / 74.55 g.mol⁻¹
Moles = 0.1133 mol
Step 2: Calculating Molarity:
Now, putting value of Moles and Volume in eq. 1,
Molarity = 0.1133 mol ÷ 0.750 L
Molarity = 0.1516 mol.L⁻¹
Molar concentration or molarity is defined as the ratio of moles of a solute dissolved in the given volume of the solvent.
Given:
Now, to calculate the number of moles, we get:
Moles = 0.113 mol
Then, the molarity of the solution will be:
Molarity = 0.1516 mol/L
Thus, the molarity of the given solution is 0.1516 mol/L. The correct answer is Option B.
Learn more about molarity here:
Do interaction can occur at room temperature
Sodium chloride is the strong electrolyte among the options provided. Strong electrolytes are substances that completely dissociate into ions when dissolved in water. Other examples of strong electrolytes include strong acids like hydrochloric acid and strong bases such as sodium hydroxide.
Among the options provided, sodium chloride is a strongelectrolyte. Electrolytes are substances that yield ions when dissolved in water. Specifically, strong electrolytes dissociate completely into ions when dissolved, leading to high conductive capacity, which is characteristic of strong electrolytes such as sodium chloride. Other substances like sugar, vinegar, or carbon tetrachloride, do not dissociate into ions when dissolved, making them non-electrolytes rather than strong electrolytes.
Examples of other strong electrolytes include strong acids like hydrochloric acid (HCl), which fully dissociates into hydrogen and chloride ions. Strong bases like sodium hydroxide (NaOH) are also strong electrolytes as they readily donate OH¯ when dissolved in water. On the other hand, weak acids and bases, such as the acids in tomato juice or vinegar, do not completely dissociate and are considered weak electrolytes.
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Answer : The concentration of NaOH is, 0.336 M
Explanation:
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Thus, the concentration of NaOH is, 0.336 M
Answer : The mass of iodine extracted can be 9796.7 mg
Explanation : Given,
Mass of thryoxine = 15.0 g
Molar mass of thryoxine = 776.86 g/mole
The molecular formula of thryoxine is,
In compound, there are 15 moles of carbon, 11 moles of hydrogen, 1 mole of nitrogen, 4 moles of oxygen and 4 moles of iodine.
First we have to determine the moles of thryoxine.
Now we have to determine the moles of iodine.
As, 1 mole of thryoxine has 4 moles of iodine
So, 0.0193 mole of thryoxine has moles of iodine
Now we have to determine the mass of iodine.
conversion used : (1 g = 1000 mg)
Therefore, the mass of iodine extracted can be 9796.7 mg
To find the molecular formula from the empirical formula, first calculate the empirical formula mass. Then, divide the molecular or molar mass by the empirical formula mass to find the number of empirical formula units per molecule. Finally, multiply the subscript of each element in the empirical formula by this number to get the molecular formula.
The process of finding the molecular formula from the empirical formula involves a few steps. First, you need to determine the empirical formula of a compound, which is the simplest positive integer ratio of atoms present in a compound. After you have the empirical formula, you can calculate the empirical formula mass by summing up the average atomic masses of all the atoms in the empirical formula.
Next, compare the compound's molecular or molar mass (which you should know or have been given) to the empirical formula mass. This comparison is done by dividing the molecular or molar mass by the empirical formula mass. This will give you the number of empirical formula units, denoted as n, per molecule of the compound.
The final step is to take the empirical formula and multiply the subscript of each element in it by n. This will give you the molecular formula of the compound.
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