What is the most precise term for quadrilateral ABCD with vertices A(3,1) , B(4,5) , C(7,5) , D(7,2) answer choices; A. KITE B. SQUARE C. RHOMBUS D. PARALLELOGRAM

Answers

Answer 1

Answer:

The most precise term for the quadrilateral ABCD with the given vertices is; A: KITE

PROPERTIES OF QUADRILATERALS

Let us first check for the slope of the diagonals. If they intersect at right angles, then they could be square, rhombus or kite.

Slope of diagonal AC = (5 - 1)/(7 - 3) = 1

Slope of diagonal BD = (2 - 5)/(7 - 4) = -1

Thus, slope 1/slope 2 = 1/-1 = - 1

This means they intersect at a perpendicular point.

Let us know find the coordinates of their midpoints. If they are the same, then it could be a square or a rhombus. If they are different, then it is a kite.

Midpoint of AC = (7 + 3)/2 AND (5 + 1)/2 = (5, 3)

Midpoint of BD = (7 + 4)/2 AND (2 + 5)/2 = (5.5, 3.5)

They are not the same and as such this is a kite.

Read more on properties of quadrilaterals at; brainly.com/question/2834250

Answer 2

Answer:

Answer:

Step-by-step explanation:

Given are the vertices of a quadrilateral.

WE have to find the name of the quadrilateral

WE have slope of AC = (5-1)/(7-3) = 1

and slope of BD = (2-5)/(7-4) = -1

Since m1m2 =-1 we get

the diagonals cut at right angles

This property is special property for square, rhombus and kite only.

Let us check if diagonals bisect each other

Mid point of AC = $((3+7)/(2) ,(1+5)/(2) =(5,3)$

Mid point of BD = $((4+7)/(2) ,(2+5)/(2) =\neq 5,3)$

Since diagonals do not bisect this is neither rhombus nor square.

Only possibility is kite

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The quotient of j and 8" can be expressed as: A. j/8 B. 8j C. j - 8 D. j + 8

How many triangles can be constructed with angles measuring 35º, 62º, and 83º?A. 0

B. 1

C. 2

D. an infinite number

Answers

B)OPTION B only 1 is your answer.

Isolate c
a=b(1/c-1/d)

Answers

A= b(1/c - 1/d)
A/b = 1/c -1/d
A/b + 1/d = 1/c
(A/b + 1/d) 1 = c

Answer: c = b/(a + 1).

Step-by-step explanation:

a = b(1/c - 1/d)

Expand RHS by first finding LCM

a = b((d — c)/cd)

a = (bd — bc)/cd

Then cross multiply

acd = bd — cd

Collect the terms having c to the LHS

acd + cd = bd

Factorise cd out of LHS

( a+ 1)dc = bd

c = bd/(a + 1)d

c = b/(a + 1).

What is the slope of the line passing through the points (1, –5) and (4, 1)?A. 2
B. -4/5
C. 5/4
D. -2

Answers

the slope is a 2
here the stpes
6/3 got 2
y2-ya
x2-x1
then you get 6/3 devide ad that you slope

3 and a Half cubes of sand transported at once. How many times do vehicle travel to transport 28 sand cubes.

Answers

Answer:

8 times

Step-by-step explanation:

28/3.5 = 8

find the equation of the line passing through the point (-4,1) and the perpendicular to the line y=1/3x+4

Answers

Answer:

The answer is

$y = - 3x - 11$

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question

$y = (1)/(3) x + 4$

Comparing it with the general equation above

Slope / m = 1/3

Since the lines are perpendicular to each other the slope of the other line is the negative inverse of the original line

That's

Slope of perpendicular line = - 3

Equation of the line using point (-4 , 1) and slope - 3 is

$y - 1 = - 3(x + 4) \n y - 1 = - 3x - 12 \n y = - 3x - 12 + 1$

We have the final answer as

y = - 3x - 11

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