MATHEMATICS HIGH SCHOOL

The first four terms of a sequence are shown below: 7, 4, 1, -2 Which of the following functions best defines this sequence? A.f(1) = 7, f(n + 1) = f(n) + 3; for n ≥ 1 B.f(1) = 7, f(n + 1) = f(n) - 3; for n ≥ 1 C. f(1) = 7, f(n + 1) = f(n) - 4; for n ≥ 1 D.f(1) = 7, f(n + 1) = f(n) + 4; for n ≥ 1

Answers

Answer 1

Answer:

Answer:

Option (B) is correct.

The sequence that best defines the function is f(1) = 7, f(n + 1) = f(n) - 3; for n ≥ 1

Step-by-step explanation:

Given sequence 7 ,4, 1,-2

We have to choose a function from given options that best defines this sequence.

Let f(n) denotes the value at nth position,

Like f(1) = 7 , so here, n= 1.

Since next term is 4 = f(2)

4 can be written as 7 - 3 = f(1) -3

Next term is 1 = f(3)

1 can be written as 4-1 = f(2) - 3

Next term is -2 = f(4)

-2 can be written as 1-3 = f(3) - 3

Thus, following the sequence and writing in general form for n

f(n+1) = f (n) -3 , n ≥ 1

Thus, option (B) is correct.

The sequence that best defines the function is f(1) = 7, f(n + 1) = f(n) - 3; for n ≥ 1

Answer 2

Answer: answer is B.f(1) = 7, f(n + 1) = f(n) - 3; for n ≥ 1

f(1) = 7
f(2) = 7 -3 = 4
f(3) = 4 -3 = 1
f(4) = 1 -3 = -2

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One hundred thirty people were asked to determine how many cups of fruit and water they consumed per day. The results are shown in the frequency table. Identify the conditional relative frequency by row. Round to the nearest percent. The conditional relative frequency that someone ate more than 2 cups of fruit, given the person drank less than or equal to 4 cups of water is approximately . The conditional relative frequency that someone ate less than or equal to 2 cups of fruit, given the person drank more than 4 cups of water is approximately .

Answers

Answer:

1. 24%

2.38%

Step-by-step explanation:

Answer:

The first one is 24% and the second one is 38%

Step-by-step explanation:

i did it on egdenuity

On #10 i need help to solve this. please and thank you.

Answers

10a. $f(x) = x - 4$
   $h(x) = √(x - 5)$
   $(f - h)(6) = (6 - 4) - (√(6 - 5))$
   $(f - h)(6) = 2 - √(1)$
   $(f - h)(6) = 2 - 1$
   $(f - h)(6) = 1$

10b. $f(x) = x - 4$
   $g(x) = (1)/(x - 3)$
   $(f * g)(x) = (x - 4)((1)/(x - 3))$
   $(f * g)(x) = (x - 4)/(x - 3)$
   Domain: (-∞, 3) ∨ (3, ∞) {x|x ≠ 3}
   Interval Notation: (3 < x < 3), (3 > x > 3)

10c. $g(x) = (1)/(x - 3)$
   $h(x) = √(x - 5)$
   $(g * h)(x) = ((1)/(x - 3))(√(x - 5))$
   $(g * h)(x) = (√(x - 5))/(x - 3)$

10d. $f(x) = x - 4$
   $g(x) = (1)/(x - 3)$
   $h(x) = \sqrt[3]{x - 7}$
   $h(x) = (f * g)(x)$
   $\sqrt[3]{x - 7} = (x - 4)((1)/(x - 3))$
   $\sqrt[3]{x - 7} = (x - 4)/(x - 3)$
   $(\sqrt[3]{x - 7})^(3) = ((x - 4)/(x - 3))^(3)$
   $x - 7 = ((x - 4)^(3))/((x - 3)^(3))$
   $(x - 3)^(3)(x - 7) = (x - 4)^(3)$
   $(x^(3) - 9x^2 + 27x + 27)(x - 7) = (x^(3) - 12x^(2) + 48x - 64)$
   $x^(4) - 16x^(3) + 90x^(2) - 216x + 189 = x^(3) - 12x^(2) + 48x - 64$
   $x^(4) + 90x^(2) - 216x + 189 = 17x^(3) - 12x^(2) + 48x - 64$
   $x^(4) + 102x^(2) - 216x + 189 = 17x^(3) + 48x - 64$
   $x^(4) + 102x^(2) + 189 = 17x^(3) + 264x - 64$
   $x^(4) + 102x^(2) + 253 = 17x^(3) + 264x$
   $x^(4) - 17x^(3) + 102x^(2) - 264x + 253 = 0$
   $x = 4\ or\ 8$

A circular logo is enlarged to fit the lid of a jar. The new diameter is 50 per cent larger than the original. By what percentage has the area of the logo increased?

Answers

25% because u have to divide the diameter of the logo to get the radius.

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Answers

Answer:

7 $m^(21)$ n^16 p^5

Step-by-step explanation:

This answer is found by diving exponents. You may be thinking its hard, but I promise you it is easier than it looks. First you look at exponent m and subtract 42-21 FIRST. that equates to 21 THEN you divide 21/3 which is 7m^21. There is only one answer with 7m^21

Classify the number -1/3.

Answers

Answer:

Step-by-step explanation:

This number is real, negative and rational.

On a spinner:
P(3) = 3/8 and the p(4) = 1/3
what is the probability of getting a 3 or 4

Answers

add the probabilities
3/8+1/3=9/24+8/24=17/24

p= 1/8 and p=1/12. those are the two probabilities

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