MATHEMATICS HIGH SCHOOL

I need all these answered please-1) 6i-i
2) (12+3i)-(2+6i)
3) 5i(1+2i)
4) 8+4i divided by 4

Answers

Answer 1
Answer: easy
pretend i is just a placeholder
but remember that i=√-1 so i²=-1
1.
6i-i=6i-1i=5i

2. (12+3i)-1(2+6i)
12+3i-2-6i
12-2+3-6i
10-3i

3.
5i(1+2i)
5i+10i²
5i+10(-1)
5i-10
-10+5i

4.
(8+4i)/4
(1/4)(8+4i)
8/2+4i/4
4+1i
4+i

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Write a subtraction problem involving regrouping that has ted reading 304 pages. Answer your question

Answers

how many pages had Ted read if the book has 502 pages, and he has 198 left to finish?

What is the KE of a 1 kg ball traveling at 30 meters per second?

Answers

KE = 1/2 mass times speed-squared KE = 1/2 (1) (900) = 450 joules

Given the domain {-5, 0, 5}, what is the range for the relation 2x+y=1

Answers

The domain x ∈ {-5; 0; 5}
the relation: 2x + y + =1 → y = 1 - 2x

Put the values of x from domain to the equation of the relation:
for x = -5 → y = 1 - 2(-5) = 1 + 10 = 11for x = 0 → y = 1 - 2(0) = 1 - 0 = 1for x = 5 → y = 1 - 2(5) = 1 - 10 = -9
Answer: {-9; 1; 11}

The ratio of D's to A's in the school was 4 to 72. If there were 1080 A's in the school this term, how many D's were there? Write your answer in a complete sentence.

Answers

Answer:

To find the number of D's in the school, we can use the given ratio of D's to A's and the number of A's provided.

The ratio of D's to A's is given as 4 to 72. This means that for every 4 D's, there are 72 A's.

We are also given that there are 1080 A's in the school this term.

To find the number of D's, we can set up a proportion using the ratio:

4 D's / 72 A's = X D's / 1080 A's

Cross-multiplying, we get:

4 * 1080 = 72 * X

Simplifying further:

4320 = 72X

Dividing both sides by 72:

X = 4320 / 72

X = 60

Therefore, there were 60 D's in the school.

Step-by-step explanation:

Danny and Mark and Evans ages combined is 80. What was there combined age three years ago?

Answers


Since there are three kids, 3x3=9. 80-9=71.  Danny and Mark and Evans ages combined is 71 years
Look At The Picture.







Good Luck!

assume the substance has a half-life of 11 years and the initial amount is 126 grams.How long will it be until only 15 % remains?

Answers

(126) times (1/2 to the x/11 power) = 15% times 126

(1/2) to the x/11 power = 0.15

Take the log of both sides :

(x/11) times log(1/2) = log(0.15)

Multiply both sides by 11 :

'x' times log(1/2) = 11 x log(0.15)

Divide both sides by " log(1/2) " :

x = 11 x log(0.15)/log(1/2) = 30.107 years (rounded)

That's the time it takes for any-size sample of this substance
to decay to 15% of its original size.
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