Answer:
Limes
Lemons
Tomatoes
Explanation:
They all contain citric acid - the others are basic
Answer:
a.) Limes
b.) Sourdough bread
g.) Lemons
h.) Tomatos
Explanation:
B. This represents a chemical change only.
C. This represents both a physical and a chemical change.
D. This represents neither a physical change nor a chemical change.
Introduction:
Understanding the amount of energy required to change the temperature of a substance is fundamental in many fields, from chemistry and physics to engineering and everyday applications. In this case, we're looking at how much energy it takes to heat a 75 g sample of aluminum.
Specific Heat Capacity of Aluminum:
To determine the energy required, we first need to consider the specific heat capacity of aluminum. The specific heat capacity (c) is a unique property of each material and represents the amount of heat energy needed to raise the temperature of 1 gram of that substance by 1 degree Celsius (or 1 Kelvin). For aluminum, the specific heat capacity (c) is approximately 0.897 J/g°C (joules per gram per degree Celsius).
Mass of the Sample:
The next piece of the puzzle is the mass of the aluminum sample. You mentioned that it's 75 grams, so we'll use that value in our calculations.
Change in Temperature:
We're looking to raise the temperature of the aluminum from 22.4°C to 94.6°C. To find the change in temperature (ΔT), we subtract the initial temperature from the final temperature:
ΔT = 94.6°C - 22.4°C = 72.2°C
Calculating the Energy:
Now, we can use the specific heat capacity formula to calculate the energy (Q) needed to raise the temperature of the aluminum sample:
Q = m * c * ΔT
Where:
Q is the energy in joules (J).
m is the mass of the sample (75 g).
c is the specific heat capacity of aluminum (0.897 J/g°C).
ΔT is the change in temperature (72.2°C).
Plugging in these values:
Q = 75 g * 0.897 J/g°C * 72.2°C
Q ≈ 4863.15 J
Conclusion:
Therefore, approximately 4863.15 joules of energy are needed to raise the temperature of a 75 g sample of aluminum from 22.4°C to 94.6°C. This calculation is essential in various scientific and practical applications, from cooking to materials engineering, and helps us understand the energy requirements for temperature changes in different substances.
b. magnetic pole.
c. magnetic domain.
d. permanent magnet.
The region around a magnet where the magnetic force is exerted is known as its
a. magnetic pole.
b. lodestone.
c. magnetic field.
d. magnetic domain.
A cluster of billions of atoms that all have magnetic fields lined up in the same way is known as a
The answer is letter C. Magnetic domain.
Answer:
i think its b tell me if im wrong if i am sorry
Explanation:
One mole of any element contains 6.022×10²³ atoms which is also called Avogadro number. The mass of 0.159 mole silicon dioxide. is 9.55g.
The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample.
Mathematically,
mole =given mass ÷ Molar mass
First of all we find the molar mass of silicon oxide
Molar mass of silicon oxide= atomic mass of silicon+2×molar mass of oxygen
Molar mass of silicon oxide=28.0855+2×16
Molar mass of silicon oxide=60.08 g/mol
Substituting the values in fisrt equation we get
0.159 mol=given mass÷60.08 g/mol
0.159 mole x 60.08 g/mol=mass
9.55g=mass of silicon oxide
Therefore the mass of 0.159 mol silicon dioxide. is 9.55g.
To know more about mole, here:
#SPJ2
Answer:
9.55 grams of SiO2
Explanation:
If the mass you mean by grams:
0.159 mole x 60.08 g (Periodic table by adding both elements)
Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:
9.55 grams of SiO2