PHYSICS HIGH SCHOOL

When a baseball player catches a baseball, the glove "gives" or moves backward. How does this movement affect the change in momentum of the baseball? The change in momentum increases because the impact time increases. The change in momentum decreases because the force decreases. The change in momentum stays the same because the ball still comes to a stop. The change in momentum depends on the initial speed of the ball and the time to stop.

Answers

Answer 1

Answer:

The change in momentum increases because the impact time increases.

Explanation:

The change in momentum of an object is also called impulse (J), and it is equal to

$J=F \Delta t$

where

F is the force applied to the object

$\Delta t$ is the time taken for the change in momentum of the object to occur (the impact time)

From the formula above, we can notice that:

- the larger the force, the larger the change in momentum

- the larger the impact time, the larger the change in momentum

In the example of the baseball caught by the glove, when the glove moves backward, the time taken for the ball to stop increases (due to the movement of the gloves). Looking at the formula, we see that this means that the impulse (the change in momentum) increases.

Answer 2

Answer:

Answer:

The change in momentum stays the same because the ball still comes to a stop.

Explanation:

here we know that momentum is defined as the product of mass and velocity

so here we know that

$P = mv$

now we know that formula to find the change in momentum is given as

$\Delta P = mv_f - mv_i$

$\Delta P = m(v_f - v_i)$

now when player moves his hand backwards then in this case final speed of the ball is zero and initial speed is same

So here we can say that there is no change in the equation but only the the to stop the ball is increased.

So here change in momentum will remain the same

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Answers

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Answers

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Why does a hot air balloon float?The shape of the balloon prides lift.
The volume of the air displaced by the balloon is less than the volume of the balloon
The weight of the air displaced is less than the volume of the balloon
The weight of the balloon is less than the weight of the air displaced by the balloon

Answers

The most accurate answer among the choices would be the fourth one, because if the weight of the air displaced is greater than the balloon's weight, the balloon will float upwards. Density of the air also plays a part. Hot air = less dense. Hope my answer has come to your help.

Right answer: The weight of the air displaced is less than the volume of the balloon

A hot air balloon is a cloth wrap that contains several thousand cubic meters of air inside (a large volume of air). The burner (which is the motor of the balloon and responsible for its elevation) heats the liquid propane to a gaseous state to generate a huge flame, thus heating the air mass inside the balloon. In this way, its density is modified with respect to the air that surrounds it, because the hot air is lighter than the outside air (less dense), causing the balloon to rise and float.

Now, if we know that the density of a body $d$ is directly proportional to its mass $m$ and inversely proportional to its volume $V$ :

$d=(m)/(V)$

We can deduce that

by increasing the volume of the body, its density will decrease.

This is proof of Archimedes' Principle:

A body totally or partially immersed in a fluid at rest, experiences a vertical upward thrust equal to the mass weight of the body volume that is displaced.

In this case the fluid is the air outside. So, the warm air inside the balloon, being less dense, will weigh less than the outside air and therefore will receive an upward pushing force or thrust that will make the balloon ascend.

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Answers

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Answers

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Answers

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If it got pushed off of the window sill and fell to the ground below,
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Naturally, this answer is only true if the window sill is more than
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at the same time.

-- 5 kilograms is a mass, not a weight.

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