2) {(1,3), (2,3), (3,3), (4,3)}
3) {(-2,4), (-2,6), (0,3), (3,7)}
4) {(-2,4), (-1,1), (0,0), (1,1)}
Option 1 , 2 and 4 is defined as a function.
And, for 1 relation;
The domain of relation = {2, -3, 4, 1}
And, Range of relation = {6, 9 ,10}
For 2 relation;
The domain of relation= {1, 2, 3, 4}
The range of relation = {3}
For 4 relation ;
The domain of the relation = {-2, -1, 0, 1}
The range of the relation = {4, 1, 0}
What is function?
A function is defined as a relation between a set of input having only one output.
Now,
The relation is;
1) {(2,6), (-3,6), (4,9), (1,10)}
Hence, The domain of relation = {2, -3, 4, 1}
And, Range of relation = {6, 9 ,10}
Clearly, Each input (domain) has only one output (range)
Hence, The given relation is function.
For,The relation;
2) {(1,3), (2,3), (3,3), (4,3)}
The domain of relation= {1, 2, 3, 4}
The range of relation = {3}
Clearly, Each input (domain) has only one output (range).
Hence, The given relation is function.
For, The function;
3) {(-2,4), (-2,6), (0,3), (3,7)}
Clearly, -2 has two image 4 and 6.
So, This relation is not a function.
For, The function;
4) {(-2,4), (-1,1), (0,0), (1,1)}
The domain of the relation = {-2, -1, 0, 1}
The range of the relation = {4, 1, 0}
Clearly, Each input (domain) has only one output (range).
Hence, This relation is a function.
Therefore,
Option 1 , 2 and 4 is defined as a function.
And, for 1 relation;
The domain of relation = {2, -3, 4, 1}
And, Range of relation = {6, 9 ,10}
For 2 relation;
The domain of relation= {1, 2, 3, 4}
The range of relation = {3}
For 4 relation ;
The domain of the relation = {-2, -1, 0, 1}
The range of the relation = {4, 1, 0}
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B. 8 left parenthesis x plus 1.5 y right parenthesis; Mike’s hourly wage is 1.5 times Harry’s.
C. 12 left parenthesis 8 x plus y right parenthesis ; Harry’s hourly wage is 8 times Mike’s.
D. 8 left parenthesis x plus 4 y right parenthesis ; Mike’s hourly wage is 4 times Harry’s.