What is the value of x? 2.5x = 35 x = 14 x = 16

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Answer 1
Answer: The value of X is 14. It is 14 because two point 2.5×14 = 35!

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Hey can you please help me posted picture of question

Enter the range of values for x

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Greetings from Brasil...

See the attached figure. The smaller the θ angle, the smaller the AB side will be. If the angle θ = 90º, then AB = 25. As θ < 90, then AB < 25

5X - 10 < 25

5X < 25 + 10

X < 35/5

X < 7

The AB side can be neither zero nor negative. So

5X - 10 > 0

5X > 10

X > 10/5

X > 2

2 < X < 7

The principal is Rs.30,000 the interest rate is 12%. Calculate the total value after 2 yearusing compound interest.

Answers

Total value=
112/100 x 112/100 x 30,000
= 37632 Rs

Answer:

37632

Step-by-step explanation:

An=A(1+12%)²

The weather in a certain locale consists of alternating wet and dry spells. Suppose that the number of days in each rainy spell is a Poisson distribution with mean 2, and that a dry spell follows a geometric distribution with mean 7. Assume that the successive durations of rainy and dry spells are independent. What is the long-run fraction of time that it rains?

Answers

Answer:

2/9

Step-by-step explanation:

The Poisson’s distribution is a discrete probability distribution. A discrete probability distribution means that the events occur with a constant mean rate and independently of each other. It is used to signify the chance (probability) of a given number of events occurring in a fixed interval of time or space.

In the long run, fraction of time that it rains = E(Number of days in rainy spell) / {E(Number of days in a rainy spell) + E(Number of days in a dry spell)}

E(Number of days in rainy spell) = 2

E(Number of days in a dry spell) = 7

In the long run, fraction of time that it rains = 2/(2 + 7) = 2/9

Final answer:

Given the parameters of the rainy spell and dry spell, the long-run fraction of time that it rains can be calculated by dividing the mean of the rainy days by the sum of the average rainy and dry days. Hence, it rains roughly 22.22% of the time in the long-term.

Explanation:

The question is asking about the long-run fraction of time that it rains, based on a rainy spell following a Poisson distribution with a mean of 2 days, and a dry spell following a geometric distribution with an average of 7 days, with the sequences being independent.

We are being asked to calculate the proportion of time that it rains in the long-run, given these distribution parameters. The Poisson and geometric distributions are often used in this type of probability assessment.

To tackle this, we need to divide the mean of the rainy days by the sum of the average rainy and dry days. Thus, the long-run fraction of time it rains is given by 2/(2+7) = 2/9.

So, in the long run, it rains roughly 22.22% (or 2/9) of the time.

Learn more about Probability Distributions here:

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2(x – 9) = 10x + 11
Help

Answers

Answer:

exact form: -28/8

decimal form: -3.625

mixed number form: -3 5/8

Answer:

x = -3.625

Step-by-step explanation:

Which polygons have at least one pair of parallel sides but are not parallelograms? Choose all that apply.

Answers

The correct option is polygon E.

What are polygons?

A polygon is a plane figure that is described by a finite number of straight line segments connected to form a closed polygonal chain.

Given that, Which polygons have at least one pair of parallel sides but are not parallelograms,

Such polygons are called trapezoid.

A trapezoid, also known as a trapezium, is a flat-closed shape having 4 straight sides, with one pair of parallel sides.

Hence, the correct polygon is E.

Learn more about polygons, click;

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C, E, F, D I’m pretty sure

(1 point) The number of households with cable TV service in a certain community, N, begins at only 55 households and has seen a fivefold increase every 17 years. Give the constants a, b, and T so that N is represented by a function of the form N=abt/T, where t is the time in years since N was first measured.

Answers

Answer:

a=55

b=5

T=17

Step-by-step explanation:

The general form of the equation is:

N(t)=ab^{(t)/(T)}

For t = 0:

N(0)=ab^{(0)/(T)}\nN(0) = a = 55\na=55

Since there has been a fivefold increase after 17 years, at t = 17, N(17) = 55*5

N(17)=55b^{(17)/(T)}\n55*5 = 55b^{(17)/(T)}\nb^{(17)/(T)} = 5

If at every 17*n years there in an increase of 5^n, one can deduct that the values for T and b are respectively 17 and 5:

b^{(t)/(T)}= 5^{(17n)/(17)}

Therefore, the function that represents N(t) is:

N(t)=55*5^{(t)/(17)}