What is 0.195 rounded to the nearest hundredth

Answers

Answer 1
Answer: the answer will be 0.20 
Answer 2
Answer: 0.20 is 0.195 roundest to the nearest hundredth 


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Use the angle difference identity to sovle 5cos2(theta) =1 for 0 degrees is less than or equal to theta is less than 360 degrees

Answers

use cos (2∅)= 2cos² ∅ -1

5(2cos²∅ -1 )=1
10cos²∅ -5 = 1
10cos²∅ = 6
cos²∅ = 0.6
cos∅ = ± √(0.6)
∅=  39.2,180 - 39.2, 180 + 39.2 , 360 - 39.2
∅ = 39.2 , 140.8 , 219.2 , 320.8 

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 5 cos 5θ

Answers

Short answer. X axis. This is a teaching lesson intended to show you what the odd and even graphs look like.
Remark

You should always try to draw these kinds of questions using a graphing calculator or some sort of program on the internet that imitates a graphing calculator. Begin by looking at the diagram on the left. Are there any clues which one you should pick?

There are. Notice the "leaf" that's on the plus x axis. It looks the same on both sides of the x axis. 

There are 4 other leaves. Do they confirm your suspicion? They should. The next leaf counter clockwise above the  one on the x axis is the mirror image of the leaf that is next clockwise to the one symmetrical about the x axis. Those two are mirror images. 

Comment
What would happen if you were give an even number of leaves? Try 4.
r = 5*cos(4 theta). Notice that 2n leaves are produced (2*4 = 8 in this case). Notice also that you have a symmetry for the origin.

Finally
If the topic interests you, go to desmos and try r = 5*sin(4*theta) and r = sin(5*theta). Are there any differences? 

Remember to be working in polar coordinates in desmos. 

Answer:

x-axis

Step-by-step explanation:

r=4 cos⁡5θ

∙Subsitute (r,-θ)in the given function

4 cos⁡〖5θ=4 cos⁡5(-θ) 〗,then r(θ)=r(π-θ)

∴Thus,it is symmetric about x-axis.

Since

4 cos⁡〖5θ≠-4 cos⁡5(π-θ) 〗

∴Thus,it is not symmetric about y-axis.

∙Since

4 cos⁡〖5θ≠-4 cos⁡5(π+θ) 〗

∴Thus,it is not symmetric about the origin

Anyone know the answer?

Answers

Hi there your answer would be d
The answer is D. 77. 

Consider the function f(x)=sin(2x)-1 and g(x)= 2 cos^2(x), both with domain [0,phi]. the line x = p intersects the graph of f in point A and the graph of g in point B. calculate the value of p for which the length of segment AB is maximal. Thank you please kindly answer this question

Answers

I think the correct value of p is 2.9 when dealing with this question.  Since AB is a vertical line between f(x) and g(x), you know you subtract the upper function by the lower function to find the distance between them.  In other words you are tying to find the x value (which can also be thought of as p) that produces the greatest value when g(x) is subtracted from f(x). The reason why g(x) is subtracted by f(x) is that g(x) is above f(x) over the domain of 0 to pi. 
I found p by making the function d(x)=g(x)-f(x).  Then I took the derivative of d(x) and found when the derivative of d(x) equals 0 since that indicates a maximum or a minimum of the function d(x).  their ended up being 2 points from 0 to pi where the derivative of d(x) equaled 0.  one at 2.9 and the other at 1.34.  The value at 1.34 is a minimum and therefore can't be the right answer.  The value at 2.9 is a maximum and is therefore the correct answer.
By the way I did all of my work on a graphing calculator which makes these types of questions a lot easier since it makes it so that you don't have to do it by hand. 
I hope this helps. Let me know if I got anything wrong in the comments so that I can try to fix it.

Geometry IXL pls correct answer !

Answers

Answer:

The answer to your question is Perimeter = 24.1 u

Step-by-step explanation:

Data

F (-4, 5)

G (1, 10)

H (-9, 10)

Process

1.- Calculate the distance from FG

dFG = \sqrt{(1 + 4)^(2) + (10 - 5)^(2)}

dFG = \sqrt{5^(2) + 5^(2)}

dFG = √(25 + 25)

dFG = √(50)

dFG = 5√(2) = 7.07

2.- Calculate the distance from GH

dGH = \sqrt{(-9 - 1)^(2) + (10 - 10)^(2)}

dGH = \sqrt{10^(2) + 0^(2)}

dGH = √(100)

dGH = 10

3.- Calculate the distance from FH

dFH = \sqrt{(-9 + 4)^(2) + ( 10 - 5)^(2)}

dFH = \sqrt{-5^(2)+ 5^(2)}

dFH = √(25 + 25)

dFH = √(50)

dFH = 5√(2) = 7.07

4.- Calculate the perimeter

Perimeter = 7.07 + 10 + 7.07

                 = 24.1 units

A quadrilateral hasno pairs of parallel
sides. What two
Shapes could it be?
(Not trapezium/trapezoid
kite, rhombus)

Answers

Answer:

parallelism

Step-by-step explanation:

I'm just looking also the answer!