The calculated division of the numbers 100 divided by 6 is 50/3
From the question, we have the following parameters that can be used in our computation:
100 divided by 6
When represented as an equation, we have
100 divided by 6 = 100/6
Divide 100 by 6
So, we have the following result
100 divided by 6 = 50/3
Using the above as a guide, we have the following:
the result is 50/3
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a² = 0.16
The graph of f(x) is shifted k units above the graph of g(x). Therefore, the option C is the correct answer.
Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.
The given functions are g(x) = 2ˣ and f(x) = 2ˣ+k
To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.
Parent Function: g(x)=2x
Horizontal Shift: None
Vertical Shift: None
Reflection about the x-axis: None
Vertical Compression or Stretch: None
So, from graph of g(x) to the graph of f(x), it shifted k units up.
Therefore, the option C is the correct answer.
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"Your question is incomplete, probably the complete question/missing part is:"
The function g(x) = 2ˣ. The f(x) = 2ˣ+k and k < 0. Which of the following statements is true?
A) The graph of f(x) is shifted k units to the left of the graph of g(x).
B) The graph of f(x) is shifted k units to the right of the graph of g(x).
C) The graph of f(x) is shifted k units above the graph of g(x).
D) The graph of f(x) is shifted k units below the graph of g(x).
Answer:
Step-by-step explanation:
Please, when you see the words "the following statements," share those possible answer choices. Thank you.
The function f(x) has the same graph as does g(x) EXCEPT that the graph has been translated down by |k| units.
If k = -5 then the graph of f(x) is the same as that of g(x) except that it's been translated down 5 units.
Answer:
The arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f g)(x) = ,
Solution:
Given, two functions are f(x) = x + 2 and g(x) = x – 2
We need to find the arithmetic combinations of given two functions.
Arithmetic functions of f(x) and g(x) are (f + g)(x), (f – g)(x), (f g)(x),
Now, (f + g)(x) = f(x) + g(x)
= x + 2 +x – 2
= 2x
Therefore (f + g)(x) = 2x
similarly,
(f - g)(x) = f(x) - g(x)
= x + 2 –(x – 2)
= x + 2 –x + 2
= 4
Therefore (f - g)(x) = 4
similarly,
(f g)(x) = f(x) g(x)
= (x + 2) (x – 2)
= x (x – 2) + 2 (x -2)
Therefore (f g)(x) =
now,
=
Hence arithmetic combinations of given functions are (f + g)(x) = 2x, (f - g)(x) = 4, (f g)(x) = ,
Answer: Nine
Step-by-step explanation:
7+9+11+13 = 40
They are all consecutive odd numbers, and add up to 40. 7 +13 is twenty, and 9+11 is also twenty, making forty. The second number in this sequence is 9
The 4 in the tensplace is worth 1/10th (or 0.1 times) the value of the 4 in the hundredsplace.
The placevalue of a number is given as:
Example:
1234.567
1 = thousand place value
2 = hundred place value
3 = tens place value
4 = ones place value
5 = tenths place value
6 = hundredths place value
7 thousandths place value
We have,
The value of a digit in a number depends on its placevalue.
The placevalue of a digit refers to the position of the digit in the number, and it determines the value of the digit in relation to the other digits in the number.
In a 3-digit number, the hundredsplace is the leftmost digit, the tens place is the middle digit, and the onesplace is the rightmost digit.
If we have a 3-digit number with a 4 in the hundredsplace and a 4 in the tensplace, the value of the 4 in the tensplace is 10 times smaller than the value of the 4 in the hundreds place.
This is because the value of a digit in a certain place is determined by the base of the number system (which is 10 in our decimal system) raised to the power of the place value.
So, in a 3-digit number, the value of the digit in the hundredsplace is 10 to the power of 2 (or 100), while the value of the digit in the tensplace is 10 to the power of 1 (or 10).
Therefore,
The 4 in the tensplace is worth 1/10th (or 0.1 times) the value of the 4 in the hundredsplace.
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The 4 in the tens place is 1/10 of the value of the 4 in the hundreds place.
4 in the tens place = 40 4 in the hundreds place = 400
400/40 = 10
so each 4 in the tens place is 1/10 of the value in the hundreds place