ALGEBRA HELP, please help with problem, and show work

Answers

Answer 1

Answer:
First of all, your second term is already wrong. When you divided 8x² by 4 ,
you should have written 2x² , not 4x² .

Make that correction, and then divide the whole thing by 'x'.

Then you'll have x² - 2x + 1 = 0 .

You should have no trouble solving that one,
(especially since it's a perfect square)

That gives you two (equal) solutions. But you should also ask yourself:
"Self ! Where is the third solution ? A cubic equation like the original
one needs three solutions."

I'll give you that one:
Look over the original equation, and look at what happens to it when x = 0 .
Then the left side becomes zero, and the equation is 0 = 0 . Since that's a
true statement, " x = 0 " is another solution of the cubic equation, and now
you have all three of them.

Answer 2

Answer: divide both sides by 4x:
x^2-2x+1=0
You can either factor, complete the square, or use the quadratic formula.
I'll factor this into (x-1)(x-1)=0
x-1=0, so x=1

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marshall took 36.75 to a fair. each ticket into the fair costs x dollars. marshall bought 3 tickets. which expression represents the amount of money, in dollars, that marshall had after he bought the tickets?

Answers

3x is less than, equal to 36.75

36.75 - 3x = the amount of money Marshall had after her bought the tickets.

If f(x)=2(x)^2 + 5 square root (x-2), complete the following statement The domain for f(x) is all real numbers _____ than or equal to 2.

Answers

Answer:

Greater.

Step-by-step explanation:

The in the function , the square root term has to give a real number if is to be real. This can only happen if because if then will give a complex number and therefore will not be real.

Thus, the domain for f(x) is all real numbers greater than or equal to 2.

Answer:

The domain for f(x) is all real numbers greater than or equal to 2.

Step-by-step explanation:

Given function:

$f(x)=2x^2+5 √(x-2)$