5/8y=-1
Answer:
It takes 3 seconds over the interval [0,3]
Step-by-step explanation:
To find when the roller coaster reaches the ground, find when d=0.
To solve divide each term by 16 and factor:
Solve for t by setting each factor to 0.
t-3=0 so t=3
t+3=0 so t=-3
This means the car is in the air from 0 to 3 second.
The time interval will be 0<t<3 or (0, 3)
A interval is a set of real numbers that contains all real numbers lying between any two numbers of the set.
Given:
d = 144 – 16t²
Now,
d>0
144 – 16t²>0
144>16t²
144/16>t²
9>t²
t<±3
Since, timecan't be negative.
So, t<3
Hence, the interval for which Greg’s car moving in the air is, 0<t<3 or (0, 3).
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Answer:
a) k should be equal to 3/16 in order for f to be a density function.
b) The probability that the measurement of a random error is less than 1/2 is 0.7734
c) The probability that the magnitude of a random error is more than 0.8 is 0.164
Step-by-step explanation:
a) In order to find k we need to integrate f between -1 and 1 and equalize the result to 1, so that f is a density function.
16k/3 = 1
k = 3/16
b) For this probability we have to integrate f between -1 and 0.5 (since f takes the value 0 for lower values than -1)
c) For |x| to be greater than 0.8, either x>0.8 or x < -0.8. We should integrate f between 0.8 and 1, because we want values greater than 0.8, and f is 0 after 1; and between -1 and 0.8.
(a) The value of k that makes f(x) a valid density function is k = 1/6.
(b) The probability that a random error in measurement is less than 1/2 is 3/4.
(c) The probability that the magnitude of the error exceeds 0.8 is 1/4.
(a) To make the given function f(x) a valid probability density function, it must satisfy the following conditions:
The function must be non-negative for all x: f(x) ≥ 0.
The total area under the probability density function must equal 1: ∫f(x)dx from -1 to 1 = 1.
Given , -1 ≤ x ≤ 1, and f(x) = 0 elsewhere, let's find the value of k that satisfies these conditions.
Non-negativity: The function is non-negative for -1 ≤ x ≤ 1, so we have ≥ 0 for -1 ≤ x ≤ 1. This means that k can be any positive constant.
Total area under the probability density function: To find the value of k, integrate f(x) over the interval [-1, 1] and set it equal to 1:
∫[from -1 to 1] = 1
∫[-1, 1] = 1
Now, integrate the function:
from -1 to 1 = 1
Simplify:
[3k - k/3 + 3k + k/3] = 1
6k = 1
k = 1/6
So, the value of k that makes f(x) a valid density function is k = 1/6.
(b) To find the probability that a random error in measurement is less than 1/2, you need to calculate the integral of f(x) from -1/2 to 1/2:
P(-1/2 ≤ X ≤ 1/2) = ∫[from -1/2 to 1/2] f(x)dx
P(-1/2 ≤ X ≤ 1/2) = ∫[-1/2, 1/2] (1/6)
Now, integrate the function:
from -1/2 to 1/2
Simplify:
(1/6)[(3/2 - 1/24) - (-3/2 + 1/24)]
(1/6)[(9/8) + (9/8)]
(1/6)(18/8)
(3/4)
So, the probability that a randomerror in measurement is less than 1/2 is 3/4.
(c) To find the probability that the magnitude of theerror (|x|) exceeds 0.8, you need to calculate the probability that |X| > 0.8. This is the complement of the probability that |X| ≤ 0.8, which you can calculate as:
P(|X| > 0.8) = 1 - P(|X| ≤ 0.8)
P(|X| > 0.8) = 1 - P(-0.8 ≤ X ≤ 0.8)
We already found P(-0.8 ≤ X ≤ 0.8) in part (b) to be 3/4, so:
P(|X| > 0.8) = 1 - 3/4
P(|X| > 0.8) = 1/4
So, the probability that the magnitude of the error exceeds 0.8 is 1/4.
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In summary, a regular octagon does not have any acute angles, while an irregular octagon can have some acute angles depending on the specific measurements of its angles.
An octagon is a polygon with eight sides. To determine the number of acute angles in an octagon, we need to understand that an acute angle is an angle that measures less than 90 degrees.
In a regular octagon (where all sides and angles are equal), each interior angle measures 135 degrees. This is because the sum of the interior angles in any octagon is given by the formula (n-2) x 180 degrees, where n is the number of sides.
In this case, (8-2) x 180 = 1080 degrees. Since all angles in a regular octagon are equal, we divide 1080 by 8 to find that each angle measures 135 degrees.
Since an acute angle measures less than 90 degrees, a regular octagon does not have any acute angles.
However, if we consider an irregular octagon (where sides and angles can have different measures), it is possible for some of the angles to be acute. The number of acute angles in an irregular octagon would depend on the specific measurements of the angles.
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