Solution of the given equation is x=2 and 0
An equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Given,
Rewrite the equation
Solve the equation
Therefore the roots are
x=2 and 0
Hence, solution of the given equation is x= 2 and 0
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O{(-3,4), (-5,4), (7, -3), (2, -9)}
O {(2, -9), (-5, -1), (-6, -3), (-5,7)}
O {(1, -8), (-9,-2), (-4,0), (4, -8)}
Step-by-step explanation:
{(2, -9), (-5, -1), (-6, -3), (-5,7)}
-5 appears twice ( this is not allowed for the function)
A . 36
B . 36
C . 72
D . 144
Answer:
The slope of X'Y' is m.
Step-by-step explanation:
It is given that XY is dilated by a scale factor of 1.3 with the origin as the center of dilation to create the image X'Y'.
Let the slope and length of XY are m and l respectively.
The dilation shows the enlargement and comparison of the figure. If the scale factor is more than 1 , then it shows enlargement. If the scale factor is more than 0 but less than 1 , then it shows compression.
The corresponding sides of image and preimage are parallel to each other. Since the slope of parallel line are equal therefore the slope of XY and X'Y' are equal, i.e., m.
The length of the image is k times of the length of preimage. The length of X'Y' is
Therefore the slope of X'Y' is m.
I'm assuming you need to find the solution to this system of equations (where the lines intersect).
We can use the substitution method to solve this system. Take the value of from the second equation and substitute it into the first:
Add to both sides of the new equation:
Now add to both sides of the equation:
Divide both sides by :
Now let's solve for by substituting the known value of into the first equation:
Simplify using subtraction:
This means our solution is:
Answer:
x = 3, y = 1
Step-by-step explanation:
Solve the following system:
{y = x - 2 | (equation 1)
y = 7 - 2 x | (equation 2)
Express the system in standard form:
{-x + y = -2 | (equation 1)
2 x + y = 7 | (equation 2)
Swap equation 1 with equation 2:
{2 x + y = 7 | (equation 1)
-x + y = -2 | (equation 2)
Add 1/2 × (equation 1) to equation 2:
{2 x + y = 7 | (equation 1)
0 x+(3 y)/2 = 3/2 | (equation 2)
Multiply equation 2 by 2/3:
{2 x + y = 7 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract equation 2 from equation 1:
{2 x+0 y = 6 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 3 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer: {x = 3, y = 1