Two possible factors for the estimated product of 2800
Answers
Answers
100 and 28.
Explanation
Factors are number that you can multiply to give a certain number.
For example, 2 × 3 = 6. In this case 2 and 3 are factors of 6.
∴ To get the factors of 2800, we have to find numbers that you can multiply to give you 2800.
2800 / 2 = 1400
∴ 2 × 1400 = 2800. ⇒ 2 and 1400 are factors of 2800.
2800/100 = 28
∴ 100 × 28 = 2800 ⇒ 100 and 28 are also factors of 2800. 2800 have many factors but two of them are 100 and 28.
280x10
That's the answer
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Answers
0 in the ones place,
1 in the tenths place,
2 in the hundredths place, and
5 in the thousandths place.
We want to round to the hundredths place, which is 2.
To do this we must look to the next digit.
If it's less than 5, we round down.
If it's more than 5, we round up.
The next digit is 5, though! So what do we do then?
Well, we would look to the next digit again and decide from that.
There isn't really a next digit to decide from, though, is there?
In that case, we just round up.
and we get 0.13
How do I find the vertex of this function?
Answers
Answer:
(-6,-69)
Step-by-step explanation:
y=2x^2 + 24x + 3
=2(x^2+12x+36)-2*36+3
=x(x+6)^2-69
vertex: when x=-6. y=-69
Answers
Answers
1)what is the y-coordinate of the solution to the system of equations? 2)what is the y-coordinate of the solution to the system of equations? y=2x+14 -4x-y=4
27+3y=2x
Answers
x-y=12
27+3y=2x
27+3y=2x
subtract 3y from both sides
27=2x-3y
2x-3y=27
x-y=12
multiply by -2
-2x+2y=-24
add them
2x-3y=27
-2x+2y=-24 +
0x-1y=3
-y=3
y=-3
y coordinate is -3
2.
y=2x+14
-4x-y=4
y=2x+14
subtract 2x from both sides
y-2x=14
mulitply both sides by -2
-2y+4x=-28
add the 2 equations
-2y+4x=-28
-y-4x=4 +
-3y+0x=-24
-3y=-24
divide both sides by -3
y=8
y coordinate is 8
1. y coordinate is y=-3
2. y coordinate is y=8
Answer:
1. -3
2. 8
Step-by-step explanation:
Answers
Answer:
80 ;
10
Step-by-step explanation:
Given :
Total number of students = μ = 140
Let :
Number of students who passed in English = E
Number of students who passed in Nepali = N
n(NnE) = 20
n(E) only = n(E) - n(NnE) = 50 - 20 = 30
Students who passed English only = 30
Number of students who passed in Nepali is twice the number who passed in English
n(N) = 2 * n(E) = 2 * 50 = 100
Number of students who passed in Nepali only
n(N) only = n(N) - n(NnE) = 100 - 20 = 80
Students who passed Nepali only = 80
The number who didn't pass both subjects :
μ - (English only + Nepali only + English and Nepali)
140 - (30 + 80 + 20)
140 - 130
= 10