Use complete sentences to describe how measurements of position in two directions (vertical and horizontal) are sufficient enough to describe the position of an object on a flat surface

Answers

Answer 1
Answer:

Answer:

We know that our world is in 3 dimensions i.e. there are three directions and so, three co-ordinates are required.

Now, if we have to find a position of an object lying on a flat surface, this means that there are only two directions and so, two co-ordinates are needed.

So, we can define the domain ( xy-axis ) in such a way that there are two axis - horizontal where right area have positive values & left area has negative values and vertical where upward side have positive values & downward side has negative values.

For e.g. if we want to find the position of a pen on the table. We will make our own xy-axis and see in which quadrant the pen lies.

Let us say that the pen lies at (2,3), this means that the position of pen is in the first quadrant or it is 2 units to the right of y-axis and 3 units up to the x-axis.

This way we can see that two directions are sufficient to find the position of an object placed on a flat surface.

Answer 2
Answer:

Final answer:

Position of an object on a flat surface can be adequately described using measurements in the vertical and horizontal directions from a certain reference point. This concept is inherent in the use of vector quantities in physics which allow us to describe motion in two perpendicular directions.

Explanation:

To describe the position of an object on a flat surface, we can use two measures: the vertical and horizontal displacement from a certain reference point. This reference point is often called the origin in a Cartesian coordinate system, which is a type of frame of reference.

Let's imagine you're looking at a map. If we want to specify a location on that map, we can describe it in terms of its distance east (or west) and north (or south) from a particular point. This technique uses horizontal and vertical measurements to describe the position.

This concept is inherent in the idea of vector quantities. In two dimensions, a vector describes motion in two perpendicular directions, such as vertical and horizontal. The principle that motions along perpendicular axes are independent allows us to analyze these two directions separately. Each vector in this context has vertical and horizontal components, and the length of the vector (representing the object's total displacement) is calculated based on these two components.

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Simplify 5t + (t - 3) - [(7t + 5) - (8 - 3t)].

-4t
4t
-10t
10t

Answers

The simplification of the expression 5t + (t - 3) - [(7t + 5) - (8 - 3t)]  using PEMDAS rule is -4t.

Thus, option 1 is correct.

A method of reducing an expression, equation, or problem to a more concise or straightforward form is referred to as simplification.

Initially the small bracket then curly brackets and at last large brackets are required to solve according to the laws of simplification using PEMDAS rules.

The given expression can be simplified as:

5t + (t - 3) - [(7t + 5) - (8 - 3t)]

5t+t-3-[7t+5-8+3t]

5t+t -3-7t-5+8-3t

-4t

The simplification of the expression 5t + (t - 3) - [(7t + 5) - (8 - 3t)] is -4t.

Thus, option 1 is correct.

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 5t + (t - 3) - [(7t + 5) - (8 - 3t)] 
=5t + (t - 3) - [(7t + 5) - (-3t + 8)] 
=5t + (t - 3) - [7t + 5 + 3t - 8] 
=5t + (t - 3) - [7t + 3t + 5 - 8] 
=5t + (t - 3) - [10t - 3] 
=5t + t - 3 - 10t + 3 
=5t + t - 10t - 3 + 3 
=-4t

One milliliter equals 10^3 liter. simplify 10^3

Answers

Hey Jackigarcia141,

10^3
= 10 to the power of three
= 10 x 10 x 10
1000

Hope this helps!

Chen :D

Write an equation that represents the distance d that Hoshi walks in t seconds

Answers

3.3t=D
T=time
D=distance

What is 2,200 yards in miles? Round to the nearest tenth of a mile.

Answers

There are 1.3 miles in 2,200 yards.

What is unit conversion?

It is the conversion of one unit to another unit with its standard conversion.

Examples:

1 hour = 60 minutes

1 minute = 60 seconds

1 km = 1000 m

We have,

2,200 yards ____(1)

1 mile = 1760 yards _____(2)

Now,

From (1) and (2),

1 mile = 1760 yards

Multiply 2,200/1760 on both sides.

2,200/1760 x 1 mile = 2,200/1760 x 1760 yards

1.25 miles = 2,200 yards

Rounding to the nearest tenths.

1.3 miles = 2,200 yards

Thus,

There are 1.3 miles in 2,200 yards.

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Answer:

1.25 mi

Step-by-step explanation:

First, we want to convert a yard into feet; recall 1 yard = 3 feet.

Then we want to divide that by the number of feet in a mile 1 mile = 5280feet.

So 2200*3 =6600, then divide by 5280

6600/5280 = 1.25 mi

2200 yard is 1.25 miles

Aaron is 15 centimeters taller than Peter, and five times Aaron's height exceeds two times Peter's height by 525 centimeters.The system of linear equations that relates Aaron's height (x) and Peter's height (y) is given by . Aaron's height is centimeters, and Peter's height is centimeters.

Answers

The answer for this problem would be x equal to 430 cm and y is equal to 325. This is computed by establishing the equations. This first equation based on first statement would be x = 15 + y and the second would be 5x = 3y + 525. Then it is solve as follows:

5x = 3y + 525 

Answer with Step-by-step explanation:

Let Aaron's height be represented by  x

and Peter's height be represented by y

Aaron is 15 centimeters taller than Peter.

i.e. x=y+15

Five times Aaron's height exceeds two times Peter's height by 525 centimeters.

i.e. 5x=2y+525

Putting x=y+15 in 5x=2y+525

5(y+15)=2y+525

5y+75=2y+525

5y-2y=525-75

3y=450

Dividing both sides by 3,we get

y=150

Putting the value of y in x=y+15,we get

x=150+15

x=165

Hence,  system of linear equations that relates Aaron's height (x) and Peter's height (y) is:

x=y+15

5x=2y+525

Aaron's height is 165 centimeters

and Peter's height is 150 centimeters

Find the coordinates of m, the midpoint of gh, for g(8,-6) and h(-14,12)

Answers

Answer:

m = (- 3, 3 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint M is

M = ( (x_(1)+x_(2) )/(2) , (y_(1)+y_(2) )/(2) ) ← midpoint formula

let (x₁, y₁ ) = g (8, - 6 ) and (x₂, y₂ ) = h (- 14, 12 ) , them midpoint m is

m = ( (8-14)/(2) , (-6+12)/(2) ) = ( (-6)/(2) , (6)/(2) ) = (- 3, 3 )