Answer:
x^3-2x^2-5x+6
Step-by-step explanation:
(x-3)(x-1)
(x^2-x-3x+3)(x+2)
x^3+2x^2-4x^2-8x+3x +6
now combine like terms
-8x + 3x = 5x
2x^2-4x^2= -2x^2
Answer:
Step-by-step explanation:
it is continuous in [0,3]
f'(x)=2x which exists in (0,3)
f(0)=0²+5=5
f(3)=3²+5=14
f(0)≠f(3)
so Rolle's theorem can't be applied.
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Answer:
noo
Step-by-step explanation:
The coordinates of the vertex of the graph are (-2, -9).
The quadratic function is described by the standard equation The graph of a quadratic function is called a parabola.
We have the quadratic function
Finding the minimum value is as follows:
Therefore, the coordinates of the vertex of the graph are (h, k), i.e.,
Other components:
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Based on the calculations, the coordinates of the vertex(h, k) of this graph are equal to (-2, -9).
In Mathematics, the standard form of a quadratic equation is given by;
ax² + bx + c = 0
Note: The graph of any quadratic function is known as a parabola.
From the given quadratic function, we have:
f(x) = x² + 4x - 5
For its coefficients, we have:
Next, we would determine the coordinates of the vertex of this graph:
x = h = -b/2a
h = -4/2(1)
h = -4/2
h = -2.
Also, we can deduce that the parabola of this graph opens upward because "a" is greater than zero (0), which produces a vertex that is a minimum:
f(h) = k
f(-2) = k = (-2)² + 4(-2) - 5
f(-2) = k = 4 - 8 - 5
k = -9.
Vertex (h, k) = (-2, -9).
Read more on vertex here: brainly.com/question/525947
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