What is the 16th term in the sequence?

2, 6, 18, 54, 162, . . .

Answers

Answer 1

Answer: it was a hard one but the answer is 258,280,326.
hope it really helped.

Answer 2

Answer: You could multiplied every thing by 3
Each time you got a product

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Please someone help me giving brainliest :)

A) Ali travelled 40 kilometers in his car and it took him 50 minutes to complete the journey. How long will it take if he had to travel 100 kilometers in the same car?

Answers

Answer:

2 hours and 5 minutes

Step-by-step explanation:

50/40=1.25 km/m

100*1.25=125 minutes

125 minutes= 2.08 hours= 2 hours and 5 minutes

What does the expression l∙w represent

Answers

It represents Length times width

Answer this question to get marked as barinliest!!!!

Answers

Answer:

the third one

Step-by-step explanation:

Answer: C

Step-by-step explanation:

A car insurance company has determined that 7% of all drivers were involved in an accident last year. If 11 drivers are selected at random, what is the probability that 3 or more were involved in an accident last year?

Answers

Using the binomial distribution, it is found that there is a 0.0369 = 3.69% probability that 3 or more were involved in an accident last year.

For each driver, there are only two possible outcomes, either they were involved in an accident, or they were not. The probability of a driver being involved in an accident is independent of any other driver, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)$

$C_(n,x) = (n!)/(x!(n-x)!)$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

7% of all drivers were involved in an accident last year, hence $p = 0.07$ .

11 drivers are selected at random, hence $n = 11$ .

The probability is:

$P(X \geq 3) = 1 - P(X < 3)$

In which:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

Then

$P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)$

$P(X = 0) = C_(11,0).(0.07)^(0).(0.93)^(11) = 0.4501$

$P(X = 1) = C_(11,1).(0.07)^(1).(0.93)^(10) = 0.3727$

$P(X = 2) = C_(11,2).(0.07)^(2).(0.93)^(9) = 0.1403$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.4501 + 0.3727 + 0.1403 = 0.9631$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.9631 = 0.0369$

0.0369 = 3.69% probability that 3 or more were involved in an accident last year.

To learn more about the binomial distribution, you can check brainly.com/question/24863377

Answer:

Therefore the probability that 3 or more were involved in an accident last year is 0.376.

Step-by-step explanation:

Binomial distribution:

A discrete random variable X having the set {0,1,2.....,n} as the spectrum, is said to have binomial distribution with parameter n= the number of trial and p = probability of getting successes in one trial if the p.m.f of X is give by

$P(X=x)=C(n,x)p^x(1-p)^(n-x)$ for x=0,1,2,....,n