MATHEMATICS HIGH SCHOOL

Write an equation for the linr that is parallel to the given lin and passes through the given point. y=5x+10; (2,14)y=1/5x+4
y=-1/5x-4
y=5x=68
y=5x+4

Answers

Answer 1
Answer: y = 5x + 10...slope here is 5. A parallel line will have the same slope.

y = mx + b
slope(m) = 5
(2,14)...x = 2 and y = 14
now we sub and find b, the y int
14 = 5(2) + b
14 = 10 + b
14 - 10 = b
4 = b

so ur parallel equation is : y = 5x + 4
Answer 2
Answer:

Answer:

He was correct

Step-by-step explanation:

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The circle graph shows the location of Oklahoma’s 77 counties in the state. Which three regions combined have 1/2 of the counties?
A.Northwest, Southwest, Southeast

B.Southwest, Northeast, Northwest

C.Northeast, Southwest, Tulsa Metro

D.Southeast, Northeast, Oklahoma City Metro

Answers

C) because if you add up percents, it adds to 50%, or 0.5 or 1/2:
Northeast 23%, Southwest 21%, Tulsa Metro 6%
23 + 21 + 6 = 50

C. Northeast, southeast,Tulsa metrois your answer

a moving company charges a flat rate of $85 plus and additional $0.17 per mile driven. How far must the company drive to earn at least $100? Round to the nearest mile.

Answers

Answer:

Atleast 88 miles

Step-by-step explanation:

We are given that

A moving company charges a flat rate=$85

Cost of 1 mile driven=$0.17

We have to find the distance drive by the company to earn at least $100.

Let x  mile drive by company .

According to question

85+0.17x\geq 100

Subtract 85  on both sides of inequality

85+0.17x-85\geq 100-85

0.17x\geq 15

Divide by 0.17 on both sides

x\geq (15)/(0.17)

x\geq 88.23

x\geq 88 (round to nearest mile)

Hence, the company must drive atleast  88 miles to earn atleast $100.
They get $85 for just getting in the truck and starting the engine.

To earn $100, they need another $15 for mileage.

$15 / 0.17 = 88.2 miles

Rounded to the nearest mile, it's 88 miles (but that still leaves them 4¢ short).

A software designer is mapping the streets for a new racing game. All of the streets are depicted as either perpendicular or parallel lines. The equation of the lane passing through A and B is -7x + 3y = -21.5. What is the equation of the central street PQ?See attachment below for picture/answer choices

Answers

Answer:

-1.5x-3.5y=-31.5

Step-by-step explanation:

we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

m1*m2=-1

In this problem line AB and line PQ are perpendicular

Step 1

Find the slope of the line AB

The equation of the line AB is

-7x+3y=-21.5

isolate the variable y

3y=7x-21.5 ------> y=(7/3)x-21.5/3

The slope of the line AB is equal to

m1=7/3

Step 2

Find the slope of the line PQ

remember that

m1*m2=-1

we have

m1=7/3 ----> slope line AB

so

substitute and solve for m2

(7/3)*m2=-1

m2=-3/7

Step 3

Find the equation of the line PQ

The equation of the line into point-slope form is equal to

y-y1=m(x-x1)

we have

m=-3/7

P(7,6)

substitute

y-6=(-3/7)(x-7)

y=(-3/7)x+3+6

y=(-3/7)x+9 -----> multiply by 7 both sides

7y=-3x+63

7y+3x=63 -----> divide by 2 both sides

1.5x+3.5y=31.5 -----> multiply by -1 both sides

-1.5x-3.5y=-31.5
its B -1.5x − 3.5y = -31.5

Part A: Solve −np − 90 < 30 for n. Show your work. Part B: Solve 5m − 3h = 45 for h. Show your work.

Answers

A.well to start you have to do  np + 90 >- 30
np > - 20
n > - 120/p

and for b. 
5m - 45 = 3h
so h = 5m/3 - 15

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Answers

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Three brothers have ages that are consecutive even integers the product of the first & third boys ages is 20 more than twice the seconds boy age.find the age of each of the boys

Answers

Let's say X is the first brother's age
x+2 is second brother, and x+4 is the third brother
Since the product of the first and third boy x(x+4) is 20 more than twice (20+x(x+2), our equation is x(x+4)=20+2(x+2)
Simplify from there and see what you get.
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