Ramon toll pass account has a value of $32. Each time he uses the toll road, $1.25 is deducted from the account. when the value drops below $10, he must add value to the toll pass, what's an inequality that represents how may times Ramon can use the the toll pass without having to add any value to the toll pass?

Answers

Answer 1
Answer:

The inequality that represents the number of toll passes without having to add any value to the toll pass is 18.

What is inequality?

It shows a relationship between two numbers or two expressions.

There are commonly used four inequalities:

Less than = <

Greater than = >

Less than and equal = ≤

Greater than and equal = ≥

We have,

Toll pass accountvalue = $32

Amount deducted with each toll pass = $1.25

The amount in the account after which value is added to the account.

= below $10

The inequality that represents the number of toll passes.

32 - 1.25x < 10

Solve for x.

32 - 1.25x < 10

32 - 10 < 1.25x

22 < 1.25x

1.25x > 22

x > 22/1.25

x > 17.6

Thus,

The number of tollpasses is 18.

Learn more about inequalities here:

brainly.com/question/20383699

#SPJ3

Answer 2
Answer: amount left=amount now-deducted
deducted=amount deducted each time times number of times
amount deducted each time =1.25
x=number of times
so

32=amount now
1.25x is deducted
so the amount left has to be greater than or equal to 10
32-1.25x≥10
minus 1.25x both sides
32≥10+1.25x
minus 10 both sides
22≥1.25x
divide both sides by 1.25
17.6≥x
you can't pass through 0.6 times so 17 times is max



the inequality is
32-1.25x≥10 whre x is the number of times that he passes

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Regular triangular pyramid has 6 cm long base edge and slant height k=9 cm. Find the lateral area of the pyramid.

Answers

Answer:

81 cm²

Step-by-step explanation:

Since, the lateral face of a triangular pyramid is a triangle,

Given,

The base edge or the base of one lateral face of pyramid, a = 6 cm,

And, the slant height or the height of the face, k = 9 cm,

Thus, the area of one lateral face of the pyramid,

A=(1)/(2)* a* k

=(1)/(2)* 6* 9

=(54)/(2)

=27\text{ square cm}

We know that, a Regular triangular pyramid has 3 lateral faces,

Hence, the total lateral area of the pyramid,

L.A.=3*\text{ The area of one lateral face}

=3* 27

=81\text{ square cm}

Answer:

hiiii your answer is 81!!

Step-by-step explanation:

Adele palmer’s charge account statement showed a previous balance of $1,500 , a finance charge of $5, new purchases of $150, and a payment of $80,00 what Is her new balance?

Answers

Answer:

New Balance = $1,575.00

Step-by-step explanation:

We can find Adele's new balance by adding the amounts she is charged to her previous balance and subtracting the amount she has paid so far:

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What is the value of y?

3y2 − 6 = 42

±___

Answers

3y²-6=42
3y²=42+6
3y²=48
y²=16
y=4
Ok so,
3y^2=42+6
3y^2=48
y^2=48/3
y^2=16
y=root of 16
y = 4

Ink cartridges weigh 1/8 pound. The total weight of the cartridges in a box is 4 1/2 pounds. How many cartridges does the box contain?

Answers

4 1/2 is 9/2 as an improper fraction, then dividing that by 1/8 (same as multiply by 8) is 72/2 or 36 cartridges.

Can someone help me with the LxWxH of a sphere and a cylinder plz

Answers


L x W x H is what you use to find the volume of a parallelopiped ...
like a cube or a box.

Cylinders and spheres don't have lengths or widths, and spheres
don't have heights either.  The formulas for their volumes look different.

Cylinders and spheres both have a 'radius' ... that's the distance from
the center of a circle out to the curved edge of the circle.  In a cylinder,
the circle is what you see when you look at one end of it.  For the sphere,
it's just the distance from the center of the sphere to the surface, because
no matter what direction you cut the sphere, if your cut goes through the
center, then you always get the same circle.

Both formulas also involve the number called 'pi'  (PIE).  It's the number
that always pops up whenever anybody is doing anything with circles
and a lot of other things in math and science.  The thing about 'pi' is
that it's impossible to write its exact value with digits ... the decimal
part of it keeps going and going and never ends.  The beginning
of 'pi' is  3.14159 26535 89792 ... and it just keeps going forever.
In school, most teachers tell you to use 3.14  for pi.  The answers
you get aren't exactly correct, but that's not a big deal, because the
answer is never the important part of the problem in school.  The
important part is that you LEARN HOW to solve the problem and
find the answer.

In math and science writing, when pi has to be written down, it's
usually not written with digits at all.  It's usually written with the
letter from the Greek alphabet called pi.  It looks like this:  π

Now, here are the formulas you asked for, for the volumes of cylinders
and spheres:

For a cylinder:        V =  π R² H

              Volume = (pi) x (square of the radius) x (height of the cylinder)

                           square of the radius means ( R x R )


For a sphere:          V = (4/3) π R³

               Volume = (4/3) x (π) x (cube of the radius)

                                       cube of the radius means ( R x R x R )

Answer:

cylinder:        V =  π R² H

            Volume = (pi) x (square of the radius) x (height of the cylinder)

                          square of the radius means ( R x R )

sphere:         V = (4/3) π R³

              Volume = (4/3) x (π) x (cube of the radius)

                                      cube of the radius means ( R x R x R )

Please help me ASAP!! #1-20 both pages please, thanks!!! :D

Answers

This is all easy!

1st page (attached)
#1 = 6(x + 3)                                 #11 = 5n - 40
#2 = 4x + 28                                 #12 = 30 + 54x
#3 = 27n + 45                               #13 = 6(4 + 3a)
#4 = 4(x - 8)                                  #14 = 88 - 66w
#5 = 5(3x - 1)                                #15 = 6(7 - 6x)
#6 = 6(5p + 3)                               #16 = 250m + 75
#7 = 24x + 56                               #17 = 2(3 + 7x)
#8 = 63a + 84                               #18 = 30p - 40
#9 = 6(7 + y)                                 #19 = 14n + 12
#10 = 3c + 12                               #20 = 10(4w + 7)

2nd page: (attached)
#1 = 5(x + 4)                                   #2 = 3x + 18
#3 = 32n + 24                                 #4 = 7(x - 5)
#5 = 6(2x - 1)                                  #6 = 4(5p + 4)
#7 = 18x + 82                                 #8 = 30 + 65a
#9 = 9(4 + y)                                  #10 = 6c + 48
#11 = 7n - 21                                 #12 = 24 + 20x
#13 = 3(7 + 5a)                              #14 = 20 - 16w
#15 = 4(8 - 3x)                               #16 = 20m - 70
#17 = 4(2 + 9x)                              #18 = 66 + 44p
#19 = 100n + 200                          #20 = 10(2w + 3)

Check for the signs when writing them down in your workbook.