The function s(V) = describes the side length, in units, of a cube with a volume of V cubic units. Jason wants to build a cube with a minimum of 64 cubic centimeters.What is a reasonable range for s, the side length, in centimeters, of Jason’s cube?

Answers

Answer 1

Answer: The function for the volume of the cube is
s(V) = V³

The minimum volume of the cube is
s(V) ≥ 64 cm³
V³ ≥ 64
V ≥ ∛64
V ≥ 4

The range of the value is from 4 to positive infinity.

Answer 2

Answer:

Answer:

greater or equal to 4

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If 5x + 15 is greater than 20, which of the following best describes possible values of x ?a) x > 5, b) x > 3, c) x > 1, d) x < 5, e) x < 1

Answers

$5x + 15 >20 \ \ |-15\n \n5x+15-15>20-15 \n \n5x>5\ \ / :5 \n \nx > 1 \n \n Answer : \ c) \ \ x > 1$

$5x+15>20 \n 5x>20-15 \n 5x>5 \n x>5/5 \n x>1$

This answer is C).

Two triangles, Triangle 1 and triangle 2, are similar. Is it a Dilation?

Answers

Answer:

You can't be sure without an image.

Step-by-step explanation:

If one moves left or right, that's a horizontal translation.

If one moves up or down, it's a vertical translation.

A dialation is when the image gets smaller or bigger.

Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)

Answers

$(x^3+10x^2+13x+39)/(x^2+2x+1)$

$x^3=x\cdot x^2$ , and $x(x^2+2x+1)=x^3+2x^2+x$ . Subtracting this from the numerator gives a remainder of

$(x^3+10x^2+13x+39)-(x^3+2x^2+x)=8x^2+12x+39$

$8x^2=8\cdot x^2$ , and $8(x^2+2x+1)=8x^2+16x+8$ . Subtracting this from the previous remainder gives a new remainder of

$(8x^2+12x+39)-(8x^2+16x+8)=-4x+31$

$-84x$ is not a multiple of $x^2$ , so we're done. Then

$(x^3+10x^2+13x+39)/(x^2+2x+1)=x+8+(-4x+31)/(x^2+2x+1)$

The rational zero theorem is sometimes called the rational root theorem. True or false? a) True b) False