A nest of ants initially contains 500 individuals. The population is increasing by 12% each week.a) How many ants will be there after :
i. 10 weeks
ii. 20 weeks

b)How many weeks will it take for the ant population to reach 2000.

Answers

Answer 1
Answer:

Answer:

a) (i) 1553 ants

(ii) 4823 ants

b) 12 weeks

Step-by-step explanation:

Given,

The initial number of ants, P = 500,

Also, the rate of increasing per week, r = 12% = 0.12,

So, the number of ants after x weeks,

A=P(1+r)^x

\implies A=500(1+0.12)^x=500(1.12)^x

a) (i) If x = 10 weeks,

The number of ants would be,

A=500(1.12)^(10)=1552.92\approx 1553

(ii) If x = 20 weeks,

The number of ants would be,

A=500(1.12)^(20)=4823.15\approx 4823

b) If A = 2000

\implies 2000 = 500(1.12)^x

4=(1.12)^x

Taking log both sides,

log(4) = xlog(1.12)

x =  12.23 ≈ 12 weeks

Answer 2
Answer: A)4, 823
B)13 Weeks

A: 500 (1 + .12)^x (which is 500 (1 + .12)^20 now)
= 4823. 15 which is ≈ 4823.

B: 2000/ y1 =  500 (1 + .12)^x / y2

12.23 so 13 weeks


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From the top of a building, 40 feet above the ground, a construction worker locates a rock at a 12° angle of depression. How far is the rock from the building? ​

Answers

Answer:

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Step-by-step explanation:

\tan(12)  =  (40)/(x)  \n x =  (40)/( \tan(12) )  \n x = 188

Answer:

I think that the other answer is WRONG

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

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