MATHEMATICS HIGH SCHOOL

The area of a rectangular room is 750 square feet. the width of the room is 5 feet less than the length of the room. which equations can be used to solve for y, the length of the room?

Answers

Answer 1

Answer:

Answer:

Width=25 ft and length=30 ft

Step-by-step explanation:

In order to find the answer let's remember that the area (A) of a rectangle is:

$A=width*length$

Let's assume that the length of the room is 'X' feet.

Becuase the problem mentioned that the width (Y) of the room is 5 feet less than the length, then:

$Y=X-5$

Now, using the area equation we have:

A=width*length

$750=X*Y$ but using the width expression we have:

$750=X*(X-5)$

$0=X^2-5X-750$

Using the root's equation we have:

$X=\frac{-b\±\sqrt{b^(2)-4ac}}{2a}$

$X=\frac{-(-5)\±\sqrt{(-5)^(2)-(4*1*(-750)}}{2*1}$

$X1=30$

$X1=-25$

Because the length (X) can't be negative, then length=30 feet. In order to find the width we have:

$Y=X-5$

$Y=30-5$

$Y=25$

So the width is 25 feet.

In conclusion the room has a width=25 ft and length=30 ft.

Answer 2

Answer: I hope this helps you

Related Questions

The possible outcomes for tossing a coin four times are shown below.1. T-T-T-T 5. T-H-T-T 9. H-T-T-T 13. H-H-T-T 2. T-T-T-H 6. T-H-T-H 10. H-T-T-H 14. H-H-T-H 3. T-T-H-T 7. T-H-H-T 11. H-T-H-T 15. H-H-H-T 4. T-T-H-H 8. T-H-H-H 12. H-T-H-H 16. H-H-H-H Tails = T Heads = H If a coin is tossed four times, what is the probability of getting exactly zero heads?
Sorry guys today is not my day :( Please show your work
Geoff planted dahlias in his garden. Dahlias have bulbs that divide and reproduce underground. In the first year, Geoff’s garden produced 8 bulbs. In the second year, it produced 16 bulbs, and in the third year it produced 32 bulbs. If this pattern continues, how many bulbs should Geoff expect in the sixth year?A. 64 B. 512 C. 128 D. 256
Anna wants to celebrate her birthday by eating pizza with her friends. For \$42.50$42.50dollar sign, 42, point, 50 total, they can buy ppp boxes of pizza. Each box of pizza costs \$8.50$8.50dollar sign, 8, point, 50.
2log3(x) = 4what is the solution?

Combine the like terms to create an equivalent expression:
\large{-2k-(-5)+1}−2k−(−5)+1

Answers

Answer:

The answer is

$- 2x + 5 + 1 - 2x + 5 + 1 = \n - 4x + 12 = \n - 4(x - 3)$

(Please see the attachment..)Find the volume of the solid where the cone and half sphere are hollow. Use 3.14 for $\pi$

Answers

This is just a cylinder, with a cone and half of a sphere carved out of it.

Just find the volume of the cylinder, then subtract the volume of the cone and the volume of the half-sphere from it, and you'll have the volume of the part that's left.

Now I'll tell you why this problem was assigned: The purpose is
to give you an opportunity to recall the formulas for the volumes
of these three shapes. To hep you recall them, here they are:

Volume of a cylinder = (pi) (radius of the round end)² (length)

Volume of a cone= (1/3) (pi) (radius of the round end)²

Volume of a whole sphere= (4/3) (pi) (radius of the whole sphere)³

Notice that in the weird contraption in the picture, the cylinder,
the cone, and the half-sphere all have the same radius.

Answer:3,349

Step-by-step explanation: (3.14)(8)^2(29)=5827.84

2/3(3.14)(8)^3=1071.787

Find the solution set of the following quadratic equations using the quadratic formula.1.) x^2 - 7x + 9 = 0
2.) 3x^2 + 10x = -3

Answers

Answer:

1) $x_1=\frac{7+√(13)}2\,,\quad x_2=\frac{7-√(13)}2$

2) $x_1=-\frac13\,,\quad x_2=-3$

Step-by-step explanation:

1)

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\n\nx=(-b\pm√(b^2-4ac))/(2a)=(-(-7)\pm√((-7)^2-4\cdot1\cdot9))/(2\cdot1)=\frac{7\pm√(49-36)}2\n\nx_1=\frac{7+√(13)}2\,,\quad x_2=\frac{7-√(13)}2$

2)

$3x^2 + 10x=-3\n\n3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\n\nx=(-b\pm√(b^2-4ac))/(2a)=(-10\pm√(10^2-4\cdot3\cdot3))/(2\cdot3)= \frac{-10\pm√(100-36)}6\n\nx_1=\frac{-10+√(64)}6=\frac{-10+8}6=-\frac13\,,\qquad x_2=\frac{-10-8}6=-3$

Consider that I have 4 sections of Stat 200. Section 001 has 40 students, section 002 has 40 students, section 003 has 30 students, and section 004 has 40, for a total of 150 students. I'd like to do a satisfaction survey with a sample size of 30, but I suspect that the section may change students' satisfaction with the course. a. Which sampling techniques could I use to ensure I get a representative sample from each section? (Check the two best answers!) A. Systematic Sampling B. Cluster Sampling C. Simple Random Sampling D. Stratified Sampling

Answers

Answer:

B. Cluster Sampling

D. Stratified Sampling

Step-by-step explanation:

B. Cluster Sampling: In cluster sampling, you divide your population (in this case, the students) into clusters (the sections) and randomly select some of those clusters for your sample. This method allows you to ensure representation from each section. You would randomly select a few sections (clusters) and survey all the students within those selected sections.

D. Stratified Sampling: In stratified sampling, you divide your population into subgroups (strata) based on certain characteristics (in this case, sections). Then, you randomly select samples from each subgroup in proportion to their size in the population. This ensures that each section is represented according to its proportion in the total population.

These methods will help you obtain a representative sample from each section while accounting for the different sizes of the sections in your Stat 200 course.

The window measured 5ft 6 inches by 2ft 9 inches about how many square inches of plastic would I need to cover the window

Answers

If you convert everything to inches you will get: 66"x33". So multiplying those you get 2176sq inches.

The surface area of a square pyramid is found using the formula 2003-05-05-00-00_files/i0080000.jpg, where b is the length of the base and h is the height. The surface area of a square pyramid whose base is 3 feet long is 51 2003-05-05-00-00_files/i0080001.jpg. What is the height of the pyramid, in feet?

Answers

Given:
base = 3 ft
surface area = 51 ft²
height = ?

surface area of a square pyramid = B + 1/2 nbl

n = number of triangle
b = base measure
l = slant height

51 ft² = (3ft)² + 1/2 * 4 * 3ft * l
51 ft² = 9ft² + (4*3ft / 2) l
51 ft² - 9 ft² = 12ft/2 * l
42 ft² = 6 ft * l
42 ft² / 6 ft = l
7 ft = l

height of the pyramid is 7 feet.

Other Questions

HELP? NEED HELP WITH SECOND ONE!!!

Pleaseeeeeeee help me 7th grade math

Which graph shows the end behavior of the graph of f(x) = 2x^6 – 2x^2 – 5?

A triangle has side lengths of 8x+4cm,9x-4y cm ,and 10-7y cm find the perimeter