2
while Philip says that the slope is 2.
Which reason correctly justifies Tom's answer?
Answer:
the answer is d
Step-by-step explanation:
i took it on usatestprep.
Answer: The coefficient before x^4 is 60
Step-by-step explanation:
Hey! So I am not an expert at this, but you have to use the binomial theorem
I have attached of the Pascals Triangle (one shows the row numbering as well)
Basically in a pascal triangle, you add the two numbers above it to get the next number below
As you can see, the rows start from 0 instead of 1
The 6th row contains the numbers 1, 6, 15, 20, 15, 6, 1 which would be the coefficient terms
NOTE: the exponents always add to 6, the first term starts at 6 and decrease it's exponent by 1 each time (6, 5, 4, 3, 2, 1, 0) and the second term increases it's exponent by 1 each time (0, 1, 2, 3, 4, 5, 6)
Using this information the third term from the sixth row (15) would be where it is x^4 (I have circled it on the second image)
It would be 15 × 2^4 × (1/2)^2 = 60
The reason why it is 2^4 and (1/2)^2 is because the third term has the exponents 4 and 2 (bolded on the NOTE) which means that the first term must be put to the power of 4 and the second term must be put to the 2nd power
Sorry for the lousy explanation. I really hope this makes sense! Let me know if this helped :)
Answer:
the answer is, Y= -27/64
Answer:
4.8
Step-by-step explanation:
the two negatives cancel each other
Answer:
4.8
Step-by-step explanation:
Since both numbers are in negative form and a division is supposed to occur, take away the negative so that the division can properly occur:
3.6 ÷ 0.75
Now simplify:
4.8
If you found my answer helpful
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Answer:
Step-by-step explanation:
The question is incomplete as the method is not given.
However, the question can still be solved.
Given
Make xi the subject in the first equation
Substitute 1 + x2 for xi in the second equation
Open bracket
Collect Like Terms
Solve for x2
Recall that:
The solution to the given system of equations is obtained through substitution. The process involves replacing a variable in one equation with an expression from the other. The final solutions are x1=1 and x2=0.
The system of equations in question is:
1) x1 - x2 = 1
2) 3x1 + x2 = 3
The method to solve this system is through substitution or elimination. First, rewrite the first equation x1 = x2 + 1. This allows us to substitute x1 - 1 for x2 in the second equation, yielding 3(x2 + 1) + x2 = 3, simplifying to 4x2 + 3 = 3. Solving for x2, we get x2 = 0. Substituting x2 into x1 = x2 + 1, we conclude that x1 = 1. Thus, the solution to the system is x1 = 1, x2 = 0.
#SPJ3
Write it in a standard form