Which air mass would produce warm, dry weather in the summer

A. Nebular is the answer

Answer:

a. 10.2 N b. 1.73 c. 58.8 N d. 10.2 N

Explanation:

a. The force that will make the block slide down the plane

This is the component of the block's weight along the plane F = mgsinθ where m = mass of block = 1.2 kg, g = 9.8 m/s² and θ = angle of incline = 60°.

So, F = mgsinθ = 1.2 kg × 9.8  m/s² × sin60°.= 10.18 N ≅ 10.2 N

b. The coefficient of friction

The coefficient of friction, μ = tanθ = tan60° = 1.73

c. The normal reaction.

This is equal to the vertical component of the block's weight. So, F = mgcosθ. Substituting the values for the variables from above, we have

F = mgcosθ = 1.2 kg × 9.8  m/s² × cos60°.= 58.8 N

d. The frictional force

Since the block does not slide, there is no net force on it. If f is the frictional force, then

F - f = ma. Since a = acceleration = 0,

F - f = 0

f = F = mgsinθ = 1.2 kg × 9.8  m/s² × sin60°.= 10.18 N ≅ 10.2 N

Answer:

6 m/s

Explanation:

At constant acceleration, the final velocity is equal to the initial velocity plus the product of time and acceleration:

v = at + v₀

We know that at t=2, v=12.  And at t=4, v=18.

12 = 2a + v₀

18 = 4a + v₀

We can solve the system of equations for v₀.  If we double the first equation:

24 = 4a + 2v₀

And subtract the second:

24-18 = 4a-4a + 2v₀ - v₀

6 = v₀

The initial velocity is 6 m/s.

Answer:

25 m/s

Explanation:

From the question,

The vertical component of the initial velocity of the base ball assuming up is positive, is given as

Vv = VsinФ................... Equation 1

Where Vv = Vertical component of the initial velocity of the base ball, V = Initial velocity of the base ball, Ф = Angle of inclination with the horizontal.

Given: V = 50 m/s, Ф = 30°

Substitute into equation 1

Vv = 50sin30°

Vv = 50(0.5)

Vv = 25 m/s.

Hence the vertical component of the initial velocity = 25 m/s

B.) Kepler is the answer, it's correct