Answer:
of would be required.
Explanation:
The quantity of solute in a solution of concentration and volume would be .
It is given that volume for the solution in this question. It is also given that the concentration of the solute in this solution is , which is the equivalent to .
Apply the equation to find the quantity of in this solution:
.
Multiply the quantity of in this solution with the formula mass of to find the corresponding mass:
.
Thus, this solution would contain of .
It would thus take of to prepare this solution.
Answer:
The required mass to prepare 2.5 L of 1.0 M NaOH solution is 100 g
Explanation:
We do this by preparing the equation:
Mass = concentration (mol/L) x volume (L) x Molar mass
Mass = 1.0 M x 2.5 L x 40 g/mol
Mass = 100 g
Answer:2.0M
Explanation
move across the membrane to the outside of the cell.
stop moving across the membrane.
continue to move across the membrane in both directions.
move across the membrane to the inside of the cell.
will continue to move across the membrane in both directions.
i hope this helps you ( c )
have a wonderful day
~hailey lee~
Since the Mg is in excess, therefore HCl will be fully consumed in the reaction.
The first step is to find the amount of HCl in mol
Let N (HCl) = amount of HCl in mol
N (HCl) = (6 mol HCL/L solution) *( 125 mL ) * (1 L/1000 mL) = 0.75 mol of HCl
Through stoichiometry
N (H2) = 0.75 mol HCl * (1 mol H2/ 2 mol of HCl)
N(H2) = 0.375 mol H2
Since we are asked for the number of grams of H2 (mass), we multiply this with the molar mass of hydrogen
M (H2) = 0.375 mol H2 ( 2 g H2 / 1 mol H2)
M (H2) = 0.75 g H2
b. good recovery sources.
c. sodium-poor.
d. highly concentrated
C. Sodium Poor - I took the test and got it correct