tonight's attendance was 100 more than double the attendance last night. If 500 attended tonight, how many attended last night?

Answers

Answer 1
Answer:

Answer: 200

Step-by-step explanation: 200 doubled would be 400 and it says that tonights attendence was 100 more than the doubled which would add up and equal 500 (400+100=500) so 200 is your answer.


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What is the present value of a $1,600 payment made in five years when the discount rate is 10 percent?

Answers

Answer:

Present value is $993.47

Step-by-step explanation:

PV = present value

Fv = future value = $1,600

Discount (i) = 10%

N = Years = 5

The formula for this is given by:

PV = FV/(1 + i)^N

PV = $1600/(1 + 0.10)^5

PV = $1600/1.1^5

PV = $1600/1.61051

PV = $993.47

Line segment of length k is divided into 3 equal parts. What is distance between midpoints of first and third segments?A) 2k/3 B) k C) k/6 D) 2k

Answers

The distance between the midpoints of the first segment and the third segment is 2k/3. Hence, option A is the right choice.

What is the mid-point of a line segment?

The mid-point of a line segment is the point from which the distance to both ends of the line segment is equal.

How to solve the question?

In the question, we are given a line segment of length k units, which is divided into 3 equal parts.

We are asked to find the distance between the midpoints of the first and third segments.

Firstly, we divide the line segment at points k/3 and 2k/3, to get three equal parts of lengths k/3 each.

Now, the mid-point of the first segment = (0 + k/3)/2 = k/6.

The mid-point of the third segment = (2k/3 + k)/2 = 5k/6

Therefore, the distance between the midpoints of the first segment and the third segment is (5k/6 - k/6) = 4k/6 = 2k/3. Hence, option A is the right choice.

Learn more about midpoints at

brainly.com/question/5566419

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Line segment of length k is divided into 3 equal parts.

so first segment is 0-k/3 and third segment is 2/3k-k

so mid-pt of 1st = k/6 and 3rd = 5/6k

so the distance in between = 5/6k-k/6 = 4/6k = 2/3k

ans is A


What is 6,720 divided by 14??

Answers

480 because 6,720 divided by 14 is 480

What is the radius of a sphere with a volume of 572 cm", to the nearest tenth of a
centimeter?

Answers

Answer:

The radius of a sphere with a volume of 572 cm^3 is 5.15 cm

Step-by-step explanation:

We need to find the radius of a sphere whose volume is: 572 cm^3

The formula used will be: Volume=(4)/(3) \pi r^3

Putting value of Volume =572 and π=3.14 we can find radius (r) of a sphere.

Volume=(4)/(3) \pi r^3\n572= (4)/(3)*3.14*r^3\n572=4.187*r^3\nr^3=(572)/(4.187)\nr^3=136.613\nTaking \ cube \ root \ on \ both \ sides:\n\sqrt[3]{r} =\sqrt[3]{136.613} \nr=5.15 \ cm

So, the radius of a sphere with a volume of 572 cm^3 is 5.15 cm

Answer:

its 5.1

Step-by-step explanation:

(4 to the 4th power)to the 3rd power​

Answers

4^7 (4 to the 7th power)

How do you calculate the approximate mean monthly salary of 100 graduatesmonthly salary number of graduate

1001-1400 1
1401-1800 11
1801-2200 14
2201-2600 38
2601 3000 36.

Answers

Answer:

The mean monthly salary of these 100 graduates is $2388.5

Step-by-step explanation:

First, lets make all of the salaries a set, so:

S = {S1,S2,S3,S4,S5}

where

S1 = {1001-1400}

S2 = {1401-1800}

S3 = {1801-2200}

S4 = {2201-2600}

S5 = {2601-3000}

Each element S1,S2,..,S5 will have it's own mean, that will be the upper range + lower range divided by 2.

So

M(S1) = (1400+1001)/2 = 2401/2 = 1200.5

M(S2) = (1401+1800)/2 = 3201/2 = 1600.5

M(S3) = (1801+2200)/2 = 4001/2 = 2000.5

M(S4) = (2201+2600)/2 = 4801/2 = 2400.5

M(S5) = (2601+3000)/2 = 5601/2 = 2800.5

To find the approximate mean, now we calculate a weigthed mean between M(S1),M(S2),...,M(S5)

So the mean will be

M = (M(S1)+11*M(S2)+14*M(S3)+38*M(S4)+36*M(S5))/100

M = 238850/100

M = 2388.5

So the mean monthly salary of these 100 graduates is $2388.5