Answer: 200
Step-by-step explanation: 200 doubled would be 400 and it says that tonights attendence was 100 more than the doubled which would add up and equal 500 (400+100=500) so 200 is your answer.
Answer:
Present value is $993.47
Step-by-step explanation:
PV = present value
Fv = future value = $1,600
Discount (i) = 10%
N = Years = 5
The formula for this is given by:
PV = FV/(1 + i)^N
PV = $1600/(1 + 0.10)^5
PV = $1600/1.1^5
PV = $1600/1.61051
PV = $993.47
The distance between the midpoints of the first segment and the third segment is 2k/3. Hence, option A is the right choice.
The mid-point of a line segment is the point from which the distance to both ends of the line segment is equal.
In the question, we are given a line segment of length k units, which is divided into 3 equal parts.
We are asked to find the distance between the midpoints of the first and third segments.
Firstly, we divide the line segment at points k/3 and 2k/3, to get three equal parts of lengths k/3 each.
Now, the mid-point of the first segment = (0 + k/3)/2 = k/6.
The mid-point of the third segment = (2k/3 + k)/2 = 5k/6
Therefore, the distance between the midpoints of the first segment and the third segment is (5k/6 - k/6) = 4k/6 = 2k/3. Hence, option A is the right choice.
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Line segment of length k is divided into 3 equal parts.
so first segment is 0-k/3 and third segment is 2/3k-k
so mid-pt of 1st = k/6 and 3rd = 5/6k
so the distance in between = 5/6k-k/6 = 4/6k = 2/3k
ans is A
480 because 6,720 divided by 14 is 480
centimeter?
Answer:
The radius of a sphere with a volume of 572 cm^3 is 5.15 cm
Step-by-step explanation:
We need to find the radius of a sphere whose volume is: 572 cm^3
The formula used will be:
Putting value of Volume =572 and π=3.14 we can find radius (r) of a sphere.
So, the radius of a sphere with a volume of 572 cm^3 is 5.15 cm
Answer:
its 5.1
Step-by-step explanation:
1001-1400 1
1401-1800 11
1801-2200 14
2201-2600 38
2601 3000 36.
Answer:
The mean monthly salary of these 100 graduates is $2388.5
Step-by-step explanation:
First, lets make all of the salaries a set, so:
S = {S1,S2,S3,S4,S5}
where
S1 = {1001-1400}
S2 = {1401-1800}
S3 = {1801-2200}
S4 = {2201-2600}
S5 = {2601-3000}
Each element S1,S2,..,S5 will have it's own mean, that will be the upper range + lower range divided by 2.
So
M(S1) = (1400+1001)/2 = 2401/2 = 1200.5
M(S2) = (1401+1800)/2 = 3201/2 = 1600.5
M(S3) = (1801+2200)/2 = 4001/2 = 2000.5
M(S4) = (2201+2600)/2 = 4801/2 = 2400.5
M(S5) = (2601+3000)/2 = 5601/2 = 2800.5
To find the approximate mean, now we calculate a weigthed mean between M(S1),M(S2),...,M(S5)
So the mean will be
M = (M(S1)+11*M(S2)+14*M(S3)+38*M(S4)+36*M(S5))/100
M = 238850/100
M = 2388.5
So the mean monthly salary of these 100 graduates is $2388.5