I need help with this plzzzz
i need help with this plzzzz - 1

Answers

Answer 1
Answer: you will need to plug in 2 for the x: f(x) -2(2)+4
= -4+4
=0
the answer in this problem is 0

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The list of a certain tool is x dollars. In store A the original selling price of the tool was $50 less than the list price, and the current selling price is 10% less than the original selling price. In store B the original selling price of the tool was 10% less than the list price, and the current selling price is $50 less than the original selling price.A) Quality A is greater
B) Quality B is greater
C) The two quantities are equal

Answers

ok so say that x=100 A: 100-50= 50 then take 10% 50 therefore it =5 B: 100-10%-50 i think it would be 10-50 which would =-40. ok now I' confused. Sorry. just try to set up the B equation and plug in a # for x and you will find your answer

expand and simplify this can you help  
(2x²−3x+4) ( x²+5x−7) 

Answers

(2x^2-3x+4) ( x^2+5x-7)= \n \n=2x^2*x^2+2x^2*5x-2x^2*7-3x*x^2-3x*5x+3x*7+4*x^2+4*5x-4*7=\n \n=2x^4+10x^3-14x^2 -3 x^3-15x^2+21x +4 x^2+20x-28=\n \n=2x^4+7x^3-25x^2 +41x -28


Assume that women's heights are normally distributed with a mean given by u = 64.3 in, and a standard deviation given by 0 = 2.7 in. (a) f 1 woman is randomly selected, find the probability that her height is less than 65 in. (b) if 43 women are randomly selected, find the probability that they have a mean heightless than 65 in. (a) The probability is approximately I. (Round to four decimal places as needed.) 4

Answers

Answer:

0.9533

Step-by-step explanation:

(a) Probability that a randomly selected woman's height is less than 65 inches:

Using the z-score formula:

=

Z=

σ

X−μ

Where:

X = 65 inches

μ = 64.3 inches

σ = 2.7 inches

=

65

64.3

2.7

0.2593

Z=

2.7

65−64.3

≈0.2593

Now, find the probability associated with this z-score, which is approximately 0.6010 (rounded to four decimal places).

(b) Probability that the mean height of 43 randomly selected women is less than 65 inches:

Using the Central Limit Theorem:

μ (mean of the sample means) remains 64.3 inches.

sample mean

σ

sample mean

 (standard deviation of the sample means) is calculated as

2.7

43

0.4115

43

2.7

≈0.4115.

Now, find the z-score for a sample mean of 65 inches:

=

65

64.3

0.4115

1.6924

Z=

0.4115

65−64.3

≈1.6924

The probability associated with this z-score is approximately 0.9533 (rounded to four decimal places).

In which number system does the equation have a solution? x^2=20 integers natural numbers C) rational numbers irrational numbers

Answers

D, irrational numbers. The opposite of squaring something is to find the square root and the square root of 20 is 4.4... 4.4 is an irrational number, therefore that is your answer. It wouldn't be rational because you can t write it as a fraction, 4.4 isn't a whole number so its not natural, and its not an integer because if you have anything right of the decimal point that is not zero, it's not an integer.

Tomika plans to run 84miles in 4weeks.If she continues the pattern how many miles will she run in a year

Answers

Answer:

She will run a distance of 1095.78 miles per year.

Explanation:

 Number of days in a year = 365.25

 Number of days in a week = 7

 Number of weeks in a year = 365.25/7 = 52.18 weeks.

 Tomika plans to run 84 miles in 4 weeks.

 Distance run by Tomika in 1 week = 84/4 = 21 miles.

 Distance run by Tomika in 1 year = 21*52.18 = 1095.78 miles

 So she will run a distance of 1095.78 miles per year.

If Tomika continues the pattern, she will run approximately 1,092 miles in a year.

How to get the miles ran

There are 52 weeks in a year, so you can divide 52 by 4 to find out how many 4-week periods there are in a year:

Number of 4-week periods in a year = 52 weeks / 4 weeks/period = 13 periods

Now, multiply the miles she runs in each 4-week period (84 miles) by the number of 4-week periods in a year (13 periods):

Total miles in a year = 84 miles/period × 13 periods

Total miles in a year = 1,092 miles

So, if Tomika continues the pattern, she will run approximately 1,092 miles in a year.

Read more on pattern here  brainly.com/question/28580633

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The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula mc023-1.jpg. If Saturn’s orbital period is 29.5 years, what is its distance from the sun?

Answers

Given that the orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a^(3/2). If Saturn’s orbital period is 29.5 years, then 29.5 = a^(3/2) a = (29.5)^(2/3) = 9.547 Therefore, Saturn's distance from the sun is 9.547 astronomical units.