Answer:
$80 - $20 = $60 left.
Step-by-step explanation:
Answer:
Step-by-step explanation:
To find the volume of the solid obtained by rotating the region bounded by the curves y=x3y=x3 and y=xy=x
about the x-axis, we'll use the method of cylindrical shells.
First, let's sketch the region bounded by these curves to better understand the shape. The intersection points of y=x3y=x3 and y=xy=x
are the points where x3=xx3=x
, which gives x=0x=0 and x=1x=1.
Now, we'll set up the integral to find the volume using cylindrical shells:
The volume VV can be calculated using the formula:
V=2π∫abx⋅(f(x)−g(x)) dxV=2π∫abx⋅(f(x)−g(x))dx
Where aa and bb are the bounds of integration (in this case, 00 and 11), and f(x)f(x) and g(x)g(x) are the heights of the shells. In this case, f(x)=x3f(x)=x3 and g(x)=xg(x)=x
.
So, the volume can be calculated as:
V=2π∫01x⋅(x3−x) dxV=2π∫01x⋅(x3−x
)dx
Now, simplify the integrand:
V=2π∫01(x4−xx) dxV=2π∫01(x4−xx
)dx
Split the integral into two parts:
V=2π∫01x4 dx−2π∫01xx dxV=2π∫01x4dx−2π∫01xx
dx
Evaluate each integral separately:
V=2π[x55]01−2π[2x5/25/2]01V=2π[5x5]01−2π[5/22x5/2]01
V=2π(15)−2π(25)=2π5V=2π(51)−2π(52)=52π
So, the volume of the solid obtained by rotating the region bounded by y=x3y=x3 and y=xy=x
about the x-axis is 2π552π cubic units.
The volume (V) of the solid obtained by rotating the region bounded by the curves about the x-axis is
To find the volume of the solid using the disk method, we integrate the cross-sectional area of each infinitesimally thin disk perpendicular to the x-axis.
The bounds of integration are determined by finding the x-values where the two curves intersect:
The radius of each disk is , and the area of each disk is
The integral for the volume becomes:
Evaluating this integral gives
In summary, the volume of the solid obtained by rotating the region bounded by about the x-axis is
The volume is calculated by integrating the cross-sectional areas of infinitesimally thin disks formed by rotating the region.
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