Ok I'm doing physics gragh an I don't know how to find the impulse on a graph

Answers

Answer 1
Answer:
OK instead of telling us what you don't know, it would actually be much more helpful if we could talk about what you DO know.

What is it a graph of ? 

-- Impulse is (force applied) x (time the force persists).
Is there force or time anywhere on the graph ?
Is there acceleration anywhere on the graph, and do you know the mass ?
With acceleration and mass, you could calculate the force.

-- Impulse is also the change in momentum.
Is there momentum anywhere on the graph ?
Is there speed anywhere on the graph, and do you know the mass ?
With speed and mass, you can calculate the momentum.

We can use what you know to solve the problem.  But we cannot use
what you don't know to solve the problem.

I just had the coolest idea:  What if you took a picture of the Physics gragh
that you're doing, and post it here along with your question ? !  Then we
would have the same information that you have, and we could show you
how to use it.



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As a tile falls from the roof of a building to the ground its momentum is conserved.
Describe Earth's three global wind belts
As the speed of a fluid increases, ____.a. the pressure decreases c. the force decreases b. the pressure increases d. the volume decreases

If the distance between two asteroids is halved, the gravitational force they exert on each other will a) Also be doubled
b) Be half as great
c) Be one fourth as great
d) Will be 1/16 as great
e) Be four times greater

Answers

Answer:

e) Be four times greater

Explanation:

Here we have to use Newton's gravitational law that relates the gravitational force between two objects with their masses (m_(1) & m_(2)) and the distance between them (r) in the next way:

F=G(m_(1)m_(2))/(r^(2)) (2)

Now if distance between asteroids is halved:

F_(2)=G(m_(1)m_(2))/(((r)/(2))^(2))

F_(2)=G(m_(1)m_(2))/((r^(2))/(4))

F_(2)=G(4m_(1)m_(2))/(r^(2))=4G(m_(1)m_(2))/(r^(2))

Note that G(m_(1)m_(2))/(r^(2)) because (1) is F so:

F_(2)=4F

It's four times greater!

Weather differs from climate in that weather can change on a daily basis and is not considered a description of year-to-year conditions of temperature and precipitation.

Answers

The statement that weather differs from climate in that weather can change on a daily basis and is not considered a description of year-to-year conditions of temperature and precipitation is true. While the climate pertains to the atmospheric conditions over long periods of time.

Answer: true

Explanation:

got it right on edge

a magnet is pushed into the center of a wire loop and then stops. what is the current in the wire loop when the wire stops moving? explain.

Answers


-- If the ends of the wire loop are open (not connected to anything)
then there's never any current in it, no matter what you do with the
magnet.

-- If there's some kind of conductor between the ends of the wire
loop, then

-- While you're pushing the magnet, a current is flowing in the wire. 
The current creates a magnetic field around the wire, and some of
the energy you're using to push gets stored in the magnetic field.

-- When you stop pushing and the magnet stops moving, the energy
stored in the magnetic field keeps the current flowing in the wire for
a short time, and then everything stops.

This all happens so fast, and lasts for such a short time, that you'd
never notice it unless you were set up with special equipment to
measure it.

Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27 and 6.35 g/cm3, respectively, and their respective atomic weights are 61.4 and 125.7 g/mol, determine whether the crystal structure for this alloy is simple cubic, face-centered cubic, or body-centered cubic. Assume a unit cell edge length of 0.395 nm.

Answers

The number of atoms in the unit cell of hypothetical alloy composed of metal A and B is 2 so the crystal structure is body-centered cubic.

What is crystal structure?

The crystal structure is the order of the atom arrangement in a repeating way. types of crystal structure are-

  • Simple cubic-In this arrangement, one atom is placed at each corner of the unit cell.
  • Face-centered cubic-In this arrangement, one atom is placed at each corner of the unit cell and one atom is placed at each face of the unit cell.
  • Body-centered cubic-In this arrangement, one atom is placed at each corner of the unit cell and one atom is placed at center of the unit cell.

Number of atom can be find out with the following formula,

n=(N\rho)/(m)[\tex]</p><p>Here, (m) is the <strong>mass </strong>of the object and (N) is <strong>Avogadro's </strong>number.</p><p></p><p><strong>Given information-</strong></p><p><strong>Hypothetical alloy </strong>is composed with metal <strong>A</strong> of 12.5 wt%.</p><p><strong>Hypothetical alloy </strong>is composed with metal <strong>B</strong> of 87.5 wt%.</p><p><strong>Densities </strong>of metals <strong>A </strong>and <strong>B</strong> are 4.27 and 6.35 g/cm 3,</p><p><strong>Atomic </strong>weights of <strong>A</strong> and <strong>B</strong> are 61.4<strong></strong>and 125.7 g/mol,</p><p></p><p>The <strong>density </strong>of the alloy is,</p><p>[tex]\rho=(1)/((12.5)/(4.27)+(87.5)/(6.35))*100=5.98[\tex]</p><p></p><p>Similarly the <strong>mass </strong>of the alloy is,</p><p>[tex]m=(1)/((12.5)/(61.4)+(87.5)/(125.7))*100=111.15[\tex]</p><p></p><p>As the <strong>mass </strong>and the <strong>density </strong>of the alloy has been obtained and the Avogadro's number is 6.023*10²³.</p><p></p><p>Put the value in the above equation to find the <strong>number </strong>of <strong>atom</strong>, we get,</p><p>[tex]n=2

Thus the number of atoms in the unit cell is 2. The crystal structure is body-centered cubic.

Learn more about the crystal structure here;

brainly.com/question/10816130

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n*(m)/(V_(c)* N_(A))

n=(\rho*V_(c)* N)/(m)....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=(1)/((12.5)/(4.27)+(87.5)/(6.35))*100

\rho=5.98

We calculate the mass of the alloy

m=(1)/((12.5)/(61.4)+(87.5)/(125.7))*100

m=111.15

Put the value into the equation (I)

n=(5.9855*(0.395*10^(-9)*10^(2))^3*6.023*10^(23))/(111.15)

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

You hear a thunder 3 seconds after you see lightning. How far away is the storm?

Answers

3 seconds (330 m) / second =
990 meter

Answer:

ikkkkrtrrr

Explanation:

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Which type of volcano is most likely to form fluid lava ?

Answers

Answer:

The answer is Hawaiian or Shield volcano.

Explanation:

Volcanoes can be classified according to their shape or according to their type of eruption.

Hawaiian volcanoes (also known as shield volcano) are volcanoes of calm eruption, because the lava is very fluid. The gases are easily released and no explosions occur. The volcano that forms has a shield appearance, since lava, being very fluid, covers a large area before solidifying.

the answer would be shield volcano hope it helped