UQuestion 2

3 pts

Select the three equations that are also equivalent to 0.5 +10b+4= 19.5

A. 106 +4= 19.5

B. 10b +4=19

C. 2(0.5 +10b+ 4) = 39

D. 10b= 19.5

E. 10b= 15

Answers

Answer 1
Answer:

Answer:

Equation (B) and (C) are equal to 0.5+10b+4=19.5

As in equation (B) when we take the 0.5 on the other side, the sign will change.Then the equation will be 10b+4=19.5-0.5

Which equals : 10b+4=19

In equation (C) 2(0.5+10b+4)=39

The 2 which is being multiplied to the bracket equation will be canceled out when we divide it , and will be divided on the other side as well so 39÷2=19.5

So the equation will become 0.5+10b+4=19.5


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How do i solve each proportion?

Answers

You have to cross multiply (multiply the numerator of the first by the denominator of the second and the numerator of the second by the denominator of the first).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[19]

(x+4)/(3) = (4)/(10)

10x+40=12

10x = -28

x=-2.8

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[21]

(4)/(n+8) = (10)/(8)

32 = 8n + 64

8n = -32

n=-4
19) (x + 4)/(3) = (4)/(10) \n \n x + 4 = (4)/(10) * 3 \n \n x = 1.2 - 4 = -2.8 \n \n x = -2.8 \n \n \n 20) (4)/(n+8) = (10)/(8) \n \n 32 = 8n + 64 \n \n 8n = 32 -64 = -32 \n \n 8n = -32 \n \n n = -4

The sum of three consecutive even integers is 108. What is the largest number?a.34
b.35
c.37
d.38

Answers

Answer:

The largest of three numbers  is 38.

Step-by-step explanation:

Given : The sum of three consecutive even integers is 108.

We have to find the largest of three consecutive even integer.

Consecutive integers are integer having a difference of one between each term . example 14 , 15, 16 ..

consecutive even integers are integers having a difference of two between them such that first term is in the form of 2n , where n is integers.

Consider the three consecutive even integers are 2n , 2n + 2 , 2n + 4

Also, given The sum of three consecutive even integers is 108.

that is 2n + 2n + 2 + 2n + 4 = 108

Simplify, we get,

6n + 6 = 108

Subtract 6 both side, we get,

6n = 102

Divide by 6 both side, we get,

n = 17

Thus, numbers are 2n = 2 × 17 = 34

2n + 2 = 34 + 2 = 36

2n + 4 = 34 + 4 = 38

Thus, The sum of three consecutive even integers is 108 then integers are 34, 36, 38 .

Thus, The largest of three numbers  is 38.

Answer:

D is the answer

Step-by-step explanation:

took the test

7 1/5 subtracted by 6 2/5 equals

Answers

Well, since the denominator is the same so you don't have to change to find an equal factor of the two, so that is good. So, 7 1/5-6 2/6 which equals 4/5. I hope I helped.

Identify the variation as direct, inverse, joint or combined.s=c/t^3
direct
inverse
joint
combined

Answers

Answer:

Inverse

Step-by-step explanation:

Assuming that c is a constant (the constant of proportion), s = c / (t^3) is a case of inverse variation:  As t increases, s decreases.

Hope this helps <3

2log3(x) = 4
what is the solution?

Answers

Answer:

x = 2/log(3) is the solution

A fair was attended by 834,009 people. Round the number to the nearest ten thousand.

Answers

A fair was attended by 834,009 people

Rounding up this number of people to nearest ten thousand.

9 has a 'ones' value

Going to the right from left:

Second last zero has a 'tens' value.

Third from last zero has a 'thousands' value

4 has 'ten thousands' value

Round up 4 and because it is less than five it converts to zero

This gives an answer of  830,000.