MATHEMATICS COLLEGE

Help pls i need a answer fast as posiable and work showed or explained

Answers

Answer 1

Answer:

Answer: 117.75

Step-by-step explanation: 70.65 divided by 0.6 = 117.75

Answer 2

Answer:

Answer:

11.775

Step-by-step explanation;

Example lang po

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According to the Insurance Institute of America, a family of four spends between $400 and $3,800 per year on all types of insurance. Suppose the money spent is uniformly distributed between these amounts.a. What is the mean amount spent on insurance?
b. What is the standard deviation of the amount spent?
c. If we select a family at random, what is the probability they spend less than $2,000 per year on insurance per year?
d. What is the probability a family spends more than $3,000 per year?

Answers

Answer: a. 2100

b. 981.5

c. 0.471

d. 0.235

Step-by-step explanation:

Given: According to the Insurance Institute of America, a family of four spends between $400 and $3,800 per year on all types of insurance.

If the money spent is uniformly distributed between these amounts.

Let A=$400 and B= $3,800

a. The mean amount spent on insurance = $(A+B)/(2)=(3800+400)/(2)=(4200)/(2)=\$2100$

b. The standard deviation of the amount spent=

$\sqrt{((B-A)^2)/(12)}\n=\sqrt{((3800-400)^2)/(12)}\n=\sqrt{((3400)^2)/(12)}$

$=(3400)/(√(12))=981.495\approx981.5$

c. To calculate, the probability they spend less than $2,000 per year on insurance per year ,it means the amount is between 400 and 2000 i.e

Amount=$2000-$400=$1600

Then P(400<insurance amount<2000) $=(amount)/(B-A)=(1600)/(3400)=0.4705\approx0.471$

d. Ia a family spends more than $3000 then the amount is between $3000 and $3800, i.e. Amount= $3800-$3000=$800

Now,

P(3000<insurance amount<3800)= $(800)/(3400)=(4)/(17)=0.235$

a. Because of the uniform distribution, the mean = the middle of both numbers, or 1/2(3800 + 400) = $2100.
b. To find the standard deviation, we take the variance ((b-a)/√12) and plug in the values:
(3800 - 400)/√12
3400/√12
~981.5
c. Again, because of uniform distribution, we just have to find the percentage that all numbers less than 2000 have in the range of 400 to 3800. To make things simple, I'm going to subtract 400 from both 3800 and 2000 so the data cuts off at 0. The equation is:
1600 = 3400 * x
16/34 = x (simplified from 1600/3400)
8/17 = x
8/17 is about 0.47, or 47%, so that's your amount.
d. same thing with c, but slightly different:
3800 - 400 = 3400, 3000 - 400 = 2600
3400 - 2600 = 800
800 = 3400 * x
8/34 = x
4/17 = x
4/17 is about 0.235.

Find an equation in standard form for the ellipse with the vertical major axis of length 10 and minor axis of length 8

Answers

Answer: The required equation of the ellipse in standard form is $(y^2)/(25)+(x^2)/(16)=1.$

Step-by-step explanation: We are given to find the equation of an ellipse in standard form with the vertical major axis of length 10 units and minor axis of length 8 units.

Since the major axis is vertical, so it will lie on the Y-axis. Let the standard form of the ellipse be given by

$(y^2)/(a^2)+(x^2)/(b^2)=1,~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where the length of major axis is 2a units and length of minor axis is 2b units.

According to the given information, we have

$2a=10\n\n\Rightarrow a=(10)/(2)\n\n\Rightarrow a=5$

and

$2b=8\n\n\Rightarrow b=(8)/(2)\n\n\Rightarrow b=4$

Substituting the values of a and b in equation (i), we get

$(y^2)/(5^2)+(x^2)/(4^2)=1\n\n\n\Rightarrow (y^2)/(25)+(x^2)/(16)=1.$

Thus, the required equation of the ellipse in standard form is $(y^2)/(25)+(x^2)/(16)=1.$

(x/h)^2+(y/v)^2=1 where h is the horizontal radius and v is the vertical radius

In this question it seem that they are saying the length of the axis and not radius so I would cut them in half so that they are radii...then:

(x/4)^2+(y/5)^2=1

x^2/16+y^2/25=1

If JK←→ and LM←→− are different names for the same line, what must be true about points J, K, L, and M ?

Answers

Step-by-step explanation:

We know that this particularly line can be named as :

JK ←→

LM ←→

This give us the following information :

The line passes through the points J and K

The line passes through the points L and M

One statement we can make is :

The points J , K , L and M are aligned. So the line passes through the points J , K , L and M.

We also know that given a line there are infinite planes that contain the line.

Given that the points J , K , L and M belong to the same line, we can state that :

There are infinite planes that contain the points J , K , L and M.

The employees of a firm that manufactures insulation are being tested for indications of asbestos in their lungs. The firm is requested to send 4 employees who have positive indications of asbestos on to a medical center for further testing. If 55% of the employees have positive indications of asbestos in their lungs, find the probability that 11 employees must be tested in order to find 4 positives. If each test costs 300 Swedish kronor, find the expected value of the total cost of conducting the tests necessary to locate the 4 positives. Swedish kronor Find the variance of the total cost necessary to locate the 4 positives.

Answers

Answer:

attached below

Step-by-step explanation:

You are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on constructing a confidence interval; however, you are not sure how many citizens should be included in the sample. If you want your sample estimate to be within 5 years of the actual mean with a confidence level of 94%, how many citizens should be included in your sample? Assume that the standard deviation of the ages of all the citizens in this community is 22 years.