MATHEMATICS HIGH SCHOOL

Pls help ASAP I’ll give brainliest

Answers

Answer 1

Answer:

Answer:

(A) 44.7°

Step-by-step explanation:

Use the law of cosines:

$cos A=(b^2+c^2-a^2)/(2bc)$
$cos A=(25^2+31^2-22^2)/(2*25*31)=0.711$
m∠A = arccos(0.711) ≈ 44.7°

Answer 2

Answer:

Using law of cosines

$\n \sf\longmapsto cosA=(b^2+c^2-a^2)/(2bc)$

$\n \sf\longmapsto cosA=(25^2+31^2-32^2)/(2(25)(31))$

$\n \sf\longmapsto cosA=(625+961-484)/(1550)$

$\n \sf\longmapsto cosA=(1102)/(1550)$

$\n \sf\longmapsto cosA=0.7109$

$\n \sf\longmapsto A=cos^(-1)(0.7109)$

$\n \sf\longmapsto A=44.7°$

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The hour hand of a clock moves from 3 to 8 o'clock through how many degrees does it move

Answers

The number of degrees does it move is 150 degrees.

The following things should be considered:

Since there are 12 parts.
Each one should we 30 degrees i.e. $= 360/ 30$
Now 8 - 3 = 5
So, the angle should be $= 5* 30$ = 150 degrees.

Therefore we can conclude that The number of degrees does it move is 150 degrees.

Learn more: brainly.com/question/17429689

There is a picture.
There 12 parts. Each one is 360/12=30°.
8-3=5 we have.
So, the angle will be 5*30=150°.

If prices increase at a monthly rate of 1.5% by what percentage do they increase in a year

Answers

The question says that prices increase at a monthly rate of 1.5%.
We know that there are 12 months in a year.
To to find the percentage of yearly increase, we just need to multiply the monthly percentage by the number of months in a year.

1.5% = 0.015

0.015 * 12 = 0.18

0.18 = 18%

Therefore, the prices increase 18% in a year.

Paloma added a garden to her painting. She has 12 rows of flowers. Each row has 13 plants in it. Each plant has 15 flowers on it. How many flowers are in Palomas garden?

Answers

Answer: 2340 flowers

Step-by-step explanation:

From the question, Paloma added a garden to her painting. She has 12 rows of flowers and each row has 13 plants in it while each plant has 15 flowers on it. To calculate the number of flowers in Palomas garden, we multiply the number of rows by the total number of plants and the number of flowers in each plant. This will be:

= 12 × 13 × 15

= 2340 flowers

Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of years since the iguanas were introduced into the garden.i(x) = 12(1.9)^x

Rewrite this function in a form that reveals the monthly growth rate of the population of iguanas in the garden. Round the growth factor to the nearest thousandth.

Answers

Answer:

$i(x)=12 * (1+(0.9)/(12))^(12x)$ and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by $i(x)=12 * (1.9)^(x)$ , where x is the number of years.

Since, $i(x)=12 * (1.9)^(x)$

i.e. $i(x)=12 * (1+0.9)^(x)$ .

Therefore, the monthly growth rate function becomes,

i.e. $i(x)=12 * (1+(0.9)/(12))^(x * 12)$ .

i.e. $i(x)=12 * (1+(0.9)/(12))^(12x)$ .

Hence, the monthly growth rate is i.e. $i(x)=12 * (1+(0.9)/(12))^(12x)$ .

Also, the growth factor is given by $(0.9)/(12)$ = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown. What is the smallest possible perimeter of the triangle, round to the nearest hundredth?

Answers

Are you doing Pythagory and theorem

Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 247 days and standard deviation sigma equals 16 days. Complete parts (a) through (f) below.

Answers

Answer:

The answer is given below

Step-by-step explanation:

a) What is the probability that a randomly selected pregnancy lasts less than 242 days

First we have to calculate the z score. The z score is used to determine the measure of standard deviation by which the raw score is above or below the mean. It is given by:

$z=(x-\mu)/(\sigma)$

Given that Mean (μ) = 247 and standard deviation (σ) = 16 days. For x < 242 days,

$z=(x-\mu)/(\sigma)=(242-247)/(16)=-0.31$

From the normal distribution table, P(x < 242) = P(z < -0.3125) = 0.3783

(b) Suppose a random sample of 17 pregnancies is obtained. Describe the sampling distribution of the sample mean length of pregnancies.

If a sample of 17 pregnancies is obtained, the new mean $\mu_x=\mu=247,$ the new standard deviation: $\sigma_x=\sigma/√(n) =16/√(17) =3.88$

c) What is the probability that a random sample of 17 pregnancies has a mean gestation period of 242 days or less

$z=(x-\mu)/(\sigma/√(n) )=(242-247)/(16/√(17) )=-1.29$

From the normal distribution table, P(x < 242) = P(z < -1.29) = 0.0985

d) What is the probability that a random sample of 49 pregnancies has a mean gestation period of 242 days or less?

$z=(x-\mu)/(\sigma/√(n) )=(242-247)/(16/√(49) )=-2.19$

From the normal distribution table, P(x < 242) = P(z < -2.19) = 0.0143

(e) What might you conclude if a random sample of 49 pregnancies resulted in a mean gestation period of 242 days or less?

It would be unusual if it came from mean of 247 days

f) What is the probability a random sample of size 2020 will have a mean gestation period within 11 days of the mean

For x = 236 days

$z=(x-\mu)/(\sigma/√(n) )=(236-247)/(16/√(20) )=-3.07$

For x = 258 days

$z=(x-\mu)/(\sigma/√(n) )=(258-247)/(16/√(20) )=3.07$

From the normal distribution table, P(236 < x < 258) = P(-3.07 < z < 3.07) = P(z < 3.07) - P(z < -3.07) =0.9985 - 0.0011 = 0.9939

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