HELP ME WITH MATH!!! So basically I have to figure out how many hours that is between the times.
HELP ME WITH MATH!!! So basically I have to figure - 1

Answers

Answer 1
Answer:

Answer: (I think its correct)

1: 8 hours and 30 minutes

2: 8 hours

3: 8 hours and 50 minutes

4: 8 hours and 45 minutes

5: 7 hours and 48 minutes

6: 11 hours 13 minutes

7: 11 hours 31 minute

Step-by-step explanation: (Im bad at explaining it)

So I got this by using counting the hours in between the times and taking out the minutes in them,then subtracting the time they took the fall asleep. Every time that has minutes I add that, if it is over 60 minutes I subtract 60 minutes. So like 30+35=65 | 65-60=5.

Lets do a problem: 9:15 (bed) | 10:30(woke up) | 30 minutes (fall asleep)

So we count how many hours in each time and we take out the minutes, so 9:00, 10:00, 11:00, so on and so forth.

So in between the hours its was 13. Then we add the minutes (15+30)

15+30=45. So the answer is 13 hours and 45 minutes, but we got to subtract 13 hours and 45 minutes which is 13 hours and 15 minutes.

Final Answer: 13 hours and 15 minutes.


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What 4 different mixed decimals that equal 11 wholes

Answers

One possible answer is:

1.2 + 2.3 + 3.4 + 4.1

Explanation:

1.2 + 2.3 = 3.5

3.5 + 3.4 = 6.9

6.9 + 4.1 = 11.0

(1.1)  +  (2.2)  +  (3.3)  +  (4.4)  =  11

Funny how that worked out.

What are the side lengths of a rectangle if the area = 40 in and the perimeter = 48 in

Answers

4, 10, 4, 10. 10*4 gives area of 40. 10+10+4+4 gives 48 as shown in question
a,b-the\ side\ lengths\ of\ a\ rectangle\n \na\cdot b=40\ [in^2]\ \ \wedge\ \ \ 2\cdot(a+b)=48\ [in]\n \n a+b=24\ \ \ \Rightarrow\ \ \ a=24-b\ \ \ \Rightarrow\ \ \ ab=(24-b)b=24b-b^2\n \nab=40\ \ \ \Rightarrow\ \ \ 24b-b^2=40\ \ \ \Rightarrow\ \ \ -b^2+24b-40=0\ /\cdot(-1)\n \nb^2-24b+40=0\ \ \Rightarrow\ \Delta=(-24)^2-4\cdot40=576-160=416=16\cdot 26\n \n

√(\Delta) =4 √(26) \ \ \ \Rightarrow\ \ \ b_1= (24-4 √(26) )/(2)=12-2 √(26)\ \Rightarrow\ a_1=12+2 √(26) \n \n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ b_2= (24+4 √(26) )/(2)=12+2 √(26)\ \Rightarrow\ a_2=12-2 √(26)

Terry opened a savings account in December with $150 and deposited $30 each month beginning in JanuaryWhat is the value of Terry's account at the end of July?

Answers

Terry had 360. The equation would be; 150+ 30*7 and solving it would be $360 because July is the seventh month of the year.
At the end of July terrys account would have $360 in all

Tricia had 4 1/8 yards of fabric to make curtains. When she finished she had 2 3/8 yards of fabric left. She said she used 2 2/8 yards of fabric for the curtains. Do you agree?

Answers

Well for this you have to do 4 1/8 - 2 3/8. You cannot subtract 1 - 3, so you have to take away 1 from three and add 8 to 1 so now the equation is 3 9/8 - 2 3/8. This is equal to 1 6/8 or 1 3/4, so no, she did not use 2 2/8 yards of fabric.
No because if you add up the fabric she 'used' and the fabric she made to make the curtains it doesn't match up with the original yards of fabric she had to make the curtains.

2 3/8+ 2 2/8= 4 5/8

4 5/8 is the supposedly original fabric she had. It's only 1/2 off from the original fabric of yards.

So no I don't agree.

-2 divided by 1/4 please show your work

Answers

-2 / 1/4
If you are dividing you have to switch 1/4 to 4/1

-2/1  / 4/1
= -8
Hope this helped

Find the solution set of this inequality|10x+20| ≤10

Answers

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

|10x+20|\leq 10

Firstly, we will find critical values

so, let's assume it is equal

|10x+20|= 10

now, we can break absolute sign

For |10x+20|= -(10x+20):

-(10x+20)= 10

we can solve for x

-10x-20= 10

Add both sides by 20

-10x-20+20= 10+20

-10x= 30

Divide both sides by -10

and we get

x=-3

For |10x+20|= (10x+20):

(10x+20)= 10

we can solve for x

10x+20= 10

Subtract both sides by 20

10x+20-20= 10-20

10x= -10

Divide both sides by 10

and we get

x=-1

so, critical values are

x=-3

x=-1

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For (-\infty,-3):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

|10* -5+20|\leq 10

|-50+20|\leq 10

30\leq 10

so, this is FALSE

For [-3,-1]:

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

|10* -2+20|\leq 10

|-20+20|\leq 10

0\leq 10

so, this is TRUE

For (-1,\infty):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

|10* 0+20|\leq 10

|0+20|\leq 10

20\leq 10

so, this is FALSE

so, solution is

[-3,-1]