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The electronic structure 1s22s22p63523p64523d8 refers to the ground state ofKr.
Ni.
Pd.
Fe.
none of the above.
Previous

Answers

Answer 1
Answer:

The given electronic configuration 1s²2s²2p⁶3s²3p⁶4s²3d⁸ is the Nickel (Ni). Therefore, option (B) is correct.

What is an electronic configuration?

The electron configuration can be explained as electrons being filled in different energy levels of an atom of a particular element. In the electron configuration, the number of electrons is usually written as a superscript of atomic subshells. For example, the electron configuration of Oxygen is written as 1s²2s²2p⁴.

The sequence of fully filled subshells that correspond to the electronic configuration of a noble gas is denoted by square brackets. The principal quantum number (n) can be used to evaluate the maximum number of electrons in an electron shell.

The value of 2n² is given the maximum number of electrons. The atomicorbitals at low energy must be filled first occupying an orbital with a higher energy level.

The total number of electrons filled in the given electronicconfiguration  1s²2s²2p⁶3s²3p⁶4s²3d⁸  is 28. The atomic number of Nickel is 28 therefore it is the configuration of Nickel.

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Answer 2
Answer: Answer:None of the above.

Because after 2p6 the rest does follow the rule of ground state format. Therefore it does make sense.

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In the first step, 4-sulfanilic acid reacts with sodium nitrate to form diazonium ion intermediate. Identify the Lewis acid and Lewis base in this reaction.

Answers

Answer:

In the formation of diazonium ion intermediate, the 4-sulfanilic acid acts as the Lewis acid, while the sodium nitrite is the Lewis base.

Explanation:

A Lewis acid is by definition an electron pair acceptor (such as the H+ ion, that can accept a pair of non-bonding electrons) and a Lewis base is an electron pair donor (such as the OH- ion, that can donate a pair of non-bonding electrons).

In the formation of diazonium ion intermediate, the 4-sulfanilic acid acts as the Lewis acid(by transference of a lone pair from its nitrogen atom), while the sodium nitrite is the Lewis base.

N.B its sodium nitrite, NaNO2 (which is slightly basic in solution) not nitrate NaNO3 (which is neutral in solution)

4-sulfanilic acid acts as Lewis acid, while Sodium nitrite is the Lewis base.

What are Lewis acid and Lewis base?

A Lewis acid is an electron pair acceptor (such as the H+ ion, that can accept a pair of non-bonding electrons) and a Lewis base is an electron pair donor (such as the OH- ion, that can donate a pair of non-bonding electrons).

In the formation of diazonium ion intermediate, the 4-sulfanilic acid acts as the Lewis acid(by transference of a lone pair from its nitrogen atom), while the sodium nitrite is the Lewis base.

Sodium nitrite, NaNO₂ (which is slightly basic in solution) not nitrate NaNO₃ (which is neutral in solution)

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10. Predict the mass of nitrogen dioxide produced if 2.30 L of ammonia are allowed to reactwith excess oxygen gas at STP?​

Answers

Answer:

Mass of nitrogen dioxide produced = 4.6 g

Explanation:

Given data:

Volume of ammonia = 2.30 L

Mass of nitrogen dioxide produced = ?

Solution:

Chemical equation:

4NH₃ + 7O₂     →      4NO₂ + 6H₂O

Number of moles of ammonia at STP:

PV = nRT

n = PV/RT

n = 1 atm × 2.30 L / 0.0821 atm.L/K.mol × 273 K

n = 2.30 atm .L / 22.414 atm.L/mol

n = 0.1 mol

Now we will compare the moles of ammonia with nitrogen dioxide from balance chemical equation.

                NH₃            :             NO₂

                 4                :               4

                 0.1             :              0.1

Mass of NO₂:

Mass = number of moles  × molar mass

Mass = 0.1 mol  × 46 g/mol

Mass = 4.6 g

1. What structural property of sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water? 2. You will have to look up the structure of this compound and comment on why it is water-soluble. Simply stating that it's polar

Answers

1. Sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water as it contains a hydrate salt sodium sulfate NaO_4S.

2. In the structure of this compound, sodium sulphate is polar in nature.

Molecular formula:

The molecular structure of sodium 4-amino-1-naphthalenesulfonate is C_(10)H_(10)NNaO_4S.

The polar part of the structure sodium sulfate NaO_4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.

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Answer: it contains a hydrate salt sodium sulfate NaO4S.

4-amino-1-naphthalenesulfonate is a sodium salt. Sodium sulfate is Polar.

Explanation:

The molecular structure of sodium 4-amino-1-naphthalenesulfonate is

C10H10NNaO4S

The polar part of the structure sodium sulfate NaO4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.

Which of the following describes the element Mg. Choose all that apply. is very reactive as a metal forms a basic solution in water is found in nature only combined with other elements reacts vigorously with alkali metals to form salts consists of diatomic molecules in elemental form is one of the group of the least reactive elements

Answers

Answer:

The statements that describe Mg are:

1. is very reactive as a metal  

2. forms a basic solution in water  

3. is found in nature only combined with other elements

Explanation:

Magnesium is a s-block chemical element that belongs to group 2 and period 3 of the periodic table. It is a reactive alkaline earth metal that exists in nature only in the combined state with elements such as carbon, calcium and oxygen.

Magnesium reacts with water at room temperature, to give strongly basic metal oxide of the formula, MgO, which forms a basic solution in water.

It also reacts vigorously with halogens such as chlorine and bromine, to form salts.

Final answer:

Magnesium is a highly reactive alkaline earth metal that forms a basic solution in water and can react vigorously with alkali metals to form salts. It consists of diatomic molecules in its elemental form.

Explanation:

Magnesium is one of the alkaline earth metals, which are found in Group 2 of the periodic table. It is a highly reactive metal that forms a basic solution in water and can react vigorously with alkali metals to form salts. Magnesium also consists of diatomic molecules in its elemental form. However, it is not one of the least reactive elements; rather, it is one of the more reactive elements in Group 2.

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A first-order decomposition reaction has a rate constant of 0.00140 yr−1. How long does it take for [reactant] to reach 12.5% of its original value? Be sure to report your answer to the correct number of significant figures.

Answers

Reactants take 504.87 yr to reach 12.5% of their original value in first-order decomposition reaction.

Equation for the first-order decomposition reaction:-

A_(t) =A_(0) e^(-kt)....(1)

Here,  A_(t) is the final concentration, t is the time,  A_(0) is the initial concentration, and k is the rate constant.

Given:-

A_(t) =0.125A_(0)

k= 0.00140yr^(-1)

Substitute the above value in equation (1) as follows:-

0.125A_(0) =A_(0) e^(-kt) \n0.125A_(0) =A_(0) e^{-k*0.00140 yr^(-1) }\nln(0.125)/(-0.00140)=t\nt=504.87 year

So, 504.87 yr does it take for the reactant to reach 12.5% of its original value.

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Final answer:

The time required for a reactant to reach 12.5% of its original value in a first-order reaction is approximately 1482 years, obtained by applying the formula for the half-life of a first-order reaction and multiplying by 3.

Explanation:

In a first-order reaction, the half-life of the reaction, which is the time it takes for half of the reactant to be consumed, is independent of the concentration of the reactant. Also, for a first-order reaction, it would take approximately 3 half-lives for the reactant to be reduced to 12.5% of its original value. The Integrated Rate Law for a First-Order Reaction can be applied to determine the time it will take.

Given the rate constant (k) is 0.00140 yr¯¹, we will use the formula for the half-life of a first-order reaction: t₁/₂ = 0.693 / k. After calculating the half-life (t₁/₂), multiply it by 3 to determine the time for the reactant concentration to reach 12.5% of its original value. Hence, it would take approximately 1482 years to reach 12.5% of the original value when rounded to the correct number of significant figures.

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Choose all the answers that apply. Which of the following is true about the sun's radiation? A) It is long-wave.
B) It is short-wave.
C) 40 percent is reflected by the atmosphere.
D) 60 percent reaches Earth's surface.
E) None of the rays are harmful.

Answers

B. It is shortwave.....

Answer:

Your answers are B,C, and D

Explanation:

Because a and e are wrong it is these three.

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