Translate the sentence into algebraic symbols.If a number is increased by 27 and then the sum is multiplied by seven, the
result is 150.

Answers

Answer 1
Answer:

9514 1404 393

Answer:

  7(x +27) = 150

Step-by-step explanation:

Let x represent the number.

  "a number increased by 27" . . . . x +27

  "the sum multiplied by 7" . . . . . 7(x +27)

  "the result is 150" . . . . . . 7(x +27) = 150


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Simplify 8X +7 - 2X -4

Answers

Answer:

6x + 3

Step-by-step explanation:

8x - 2x + 7 -4

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A boat is heading towards a lighthouse, whose beacon-light is 131 feet above thewater. From point A, the boat's crew measures the angle of elevation to the beacon,
5°, before they draw closer. They measure the angle of elevation a second time from
point B at some later time to be 21°. Find the distance from point A to point B.
Round your answer to the nearest tenth of a foot if necessary.

Answers

Answer:

Step-by-step explanation:

Assuming a flat earth

initial measurement

tan5 = 131 / d₁

d₁ = 131/tan5 = 1,497.3368... ft

d₂ = 131/tan21 = 341.2666674...ft

distance from A to B

1497.3368 - 341.26666 = 1,156.1 ft

Rather daring to specify to the answer to the nearest tenth of a foot when no given measurement accuracy is even close to that same precision.

Final answer:

This is a trigonometry problem that can be solved by using the tangent function to find the distances from the boat to the lighthouse at two different angles of elevation, and then subtracting to find the distance travelled by the boat.

Explanation:

This question involves the concept of trigonometry, specifically inverse trigonometric functions. We can solve it by creating two right triangles and using the trigonometric function known as tangent. Due to the nature of the problem, we will consider the lighthouse as the opposite side while the distance from the boat to the lighthouse will serve as the adjacent side.

When the boat is at point A, we can write the following equation using the tangent of 5° - tan(5°) = 131/DistanceA. Solve this equation to find DistanceA.

Next, do the same when the boat is at point B. The equation for this scenario is - tan(21°) = 131/DistanceB. Resolve this equation to find DistanceB.

The distance from point A to B (which is what the question asks for) is just the difference between DistanceA and DistanceB. Make sure to take the absolute value to avoid a negative distance, and round the result to the nearest tenth of a foot if necessary.

Learn more about Trigonometry here:

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A probability model includes p(red)=2/7 and P(blue)=3/14. Select all the probabilities that could complete the model.Answer Key:
A: P(green)= 2/7, P(yellow)=2/7
B: P(green)=3/8, P(yellow)=1/8
C: P(green)=1/4 P(yellow)=1/4
D: P(green)= 5/21 Pyellow)= 11/21 E. P(green)= 3/7 P(yellow)=1/14

Answers

Answer:

The answer is "Option D".

Step-by-step explanation:

In this question, the shape of the model is not declared that why we assume that it has four sides in which two sides are given that is:

\to P(red)=(2)/(7) \n\n\to P(blue)=(3)/(14)

other probabilities  are:

\to P(green)= (5)/(21) \n\n\to P(yellow)= (11)/(21)

Cost of a dozen pens is ₹ 180 and cost of 8 ball pens is ₹ 56. Find the ratio of the cost of a pen to the cost of a ball pen. [1 ½ m]

Answers

Answer:

Ratio of cost of a pen to cost of a ball pen is 15:7

Step-by-step explanation:

Given that:

Cost of dozen pens = ₹180

Unit rate = (180)/(12)

Unit rate = ₹ 15 per pen

Cost of 8 ball pens = ₹ 56

Unit rate = (56)/(8)

Unit rate = ₹7 per ball pen

Ratio of cost of a pen to cost of a ball pen,

15 : 7

Hence,

Ratio of cost of a pen to cost of a ball pen is 15:7

Parallel lines r and s are cut by two transversals, parallel lines t and u. Lines r and s are crossed by lines t and u to form 16 angles. Clockwise from top left, at the intersection of r and t, the angles are 1, 2, 3, 4; at the intersection of s and t, 5, 6, 7, 8; at the intersection of u and s, 9, 10, 11, 12; at the intersection of u and r, 13, 14, 15, 16. Which angles are alternate interior angles with angle 3? Angle5 and Angle13 Angle7 and Angle15 Angle6 and Angle16 Angle8 and Angle14 Mark this an

Answers

Answer:

5 and 13

Step-by-step explanation:

I got it right on edge

Answer:

5 and 13, got in right in edge 2020

Step-by-step explanation:

Consider the polynomials p(x) = 3x + 27x^2 and q(x)= 2 . Find the x -coordinate(s) of the point(s) of intersection of these two polynomials. What is the sum of these x -coordinates? (If there is only one point of intersection, give the corresponding x -coordinate.)

Answers

Answer:

The x -coordinate(s) of the point(s) of intersection of these two polynomials are x=(2)/(9)\approx0.2222,\:x=-(1)/(3)\approx-0.3333

The sum of these x -coordinates is (2)/(9)+\left(-(1)/(3)\right)=-(1)/(9)

Step-by-step explanation:

The intersections of the two polynomials, p(x) and q(x), are the roots of the equation p(x) = q(x).

Thus, 3x + 27x^2=2 and we solve for x

3x+27x^2-2=2-2\n27x^2+3x-2=0\n\left(27x^2-6x\right)+\left(9x-2\right)\n3x\left(9x-2\right)+\left(9x-2\right)\n\left(9x-2\right)\left(3x+1\right)=0

Using Zero Factor Theorem: = 0 if and only if = 0 or = 0

9x-2=0\n9x=2\nx=(2)/(9)

3x+1=0\n3x=-1\nx=-(1)/(3)

The solutions are:

x=(2)/(9)\approx0.2222,\:x=-(1)/(3)\approx-0.3333

The sum of these x -coordinates is

(2)/(9)+\left(-(1)/(3)\right)=-(1)/(9)

We can check our work with the graph of the two polynomials.