A 50-kg child on a skateboard experiences a 75-N force. What is the expected acceleration of the child?

Answers

Answer 1

Answer: Since the force is 75-N and the kid is 50kg then the speed will be more than equal. It will move fast, but not so fast, but if the force was higher then it will go faster.

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At what temperature (in C) will a sample of gas occupy 91.3 L if it occupies 45.0 L at 70.0°C? Assume constant pressure.)
What does the group number of A elements in the A/B numbering system)tell about valence electrons?A. The A group number tells which period the valence electrons areinB. The A group number tells how much mass the elements have.C. All elements in the same A group will have the same number ofvalence electrons.D. All elements in the A group will have the same valence electronsas the B group.

Why earths atmosphere is like the glass in a greenhouse

Answers

Answer:

Explanation:

That's because the glass walls of the greenhouse trap the Sun's heat. The greenhouse effect works much the same way on Earth. Gases in the atmosphere, such as carbon dioxide, trap heat just like the glass roof of a greenhouse. These heat-trapping gases are called greenhouse gases.

Name two different ecosystems.Name one living part of each ecosystem.Name one non living part of each ecosystem.

Answers

Ecosystems: Coral Reef, Savanah
Living: In coral reef; clown fish In Savanah: Emu
Nonliving: In Coral reef: Water In Savanah: sun

there is a freshwater ecosystem one living thing is fishes a non living thing is lots of concentrations of dissolved oxygen. Another ecosystem would be a forest ecosystem one living thing would be insects one non living would be water

The density of gold is 19.3 g /cm cubed The density of iron pyrite is 5.0 g /cm cubed. Is a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget

Answers

If you clear volume in the density equation:

$\rho = (m)/(V)\ \to\ V = (m)/(\rho)$

The greater the density the lower the volume. This means, the volume of gold nugget will be smaller than the volume of iron pyrite nugget.

$V_(gold) = (m)/(\rho) = (50\ g)/(19.3\ g/cm^3) = \bf 2.59\ cm^3$

$V_(iron) = (m)/(\rho) = (50\ g)/(5.0\ g/cm^3) = \bf 10\ cm^3$

Which element is classified as an alkali metal?

Answers

Answer:

Explanation:

Alkali metals are in group 1 (the first column on the periodic table) including Li, Na, K, etc.

Which of the following objects is NOT a part of our solar system? A. the North Star B. the dwarf planet Pluto C. the asteroid belt D. Jupiter’s moons

Answers

Of the items on the list, only choice A. (The North Star) is not a part of our solar system. The items in our solar system are those objects that orbit our Sun and are enclosed inside the Oort Cloud. The North Star (named Polaris) is a star located quite some distance away from the Earth.
Hope that helped! =)

The answer is A because the North Star is a star and stars are suns not in our solar system. Hope this helped!

Which ion has the smallest radius?
(1) O2-
(2) S2-
(3) Se2-
(4) Te2-

Answers

Answer:

Option-1 (O²⁻) is the correct answer.

Explanation:

All given anions contains same charge. So, we can ignore the effect of charge on these anions.

As we know all given compounds belongs to same group (Group 6) in periodic table. And from top to bottom along the group the elements are placed as,

Oxygen O

Sulfur S

Selenium Se

Tellurium Te

Hence, moving from top to bottom along the group the number of shells increases. And with increase in number of shell the atomic or ionic radii increases. As Oxygen is present at the top of the group, therefore, it has the smallest radius due to less number of shells.

O²⁻ ion has the smallest radius

Further explanation

In an atom there are levels of energy in the shell and sub shell.

This energy level is expressed in the form of electron configurations.

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f. The maximum number of electrons for each sub shell is

s: 2 electrons
p: 6 electrons
d: 10 electrons and
f: 14 electrons

Charging electrons in the sub shell uses the following sequence:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.

Each sub-shell also has an orbital shown in the form of a square in which there are electrons symbolized by half arrows

The atomic radius shows the distance of the atomic nucleus to the electrons in the outer shell

From left to right in the period system the atomic radius gets smaller, while from one group from top to bottom the atomic radius gets longer

The more the number of shells the atom has, the radius of the atom getting longer, but if the number of shells is the same, the larger atomic number has shorter radius because the core charge is greater so that the attraction of the nucleus to the electrons is stronger

In the ions

(1) O²⁻

(2) S²⁻

(3) Se²⁻

(4) Te²⁻

All of these ions are ions from the elements of the VIA group in the periodic system. This group consists of oxygen (O), sulfur (S), selenium (Se), tellurium (Te), and polonium (Po).

The periodic system is arranged in the order of atomic numbers, whereas in this VIA group from top to bottom, the atomic number gets bigger

Element O

Atomic Number: 8

Electron configuration: 1s² 2s² 2s⁴ (number of shells 2)

Element S

Atomic Number: 16

Electron configuration: [Ne] 3s² 3p⁴ (number of shells 3)

Element Se

Atomic Number: 34

Electron configuration: [Ar] 3d¹⁰ 4s²4p⁴ (number of shells 4)

Element Te

Atomic Number: 52

Electron configuration: [Cr] 4d10 5s² 5p⁴ (number of shells 5)

From the configuration of the electron shows that the lower the shell owned by the elements of the VIA group the greater (from 2 to 5) so that the radius is also getting longer/bigger

Because what is being asked is the radius of the ion, the electron configuration of each element is equally reduced by 2 electrons, but the number of shells remains the same

(1)O²⁻

Electron configuration: 1s² 2s² 2s²

(2) S²⁻

Electron configuration: [Ne] 3s² 3p²

(3) Se²⁻

Electron configuration: [Ar] 3d¹⁰ 4s²4p²

(4) Te²⁻

Electron configuration: [Cr] 4d¹⁰ 5s² 5p²

Because the amount of shell from the Oxygen ion is the smallest, the radius of the O²⁻ is also the smallest