Answer:
Sexual reproduction can be described as the method of reproduction in which the offsprings produced will have half the chromosomes as compared to the parent cell. The other half of the chromosomes to make a complete set would arise from the other parent. In this way, the offspring produced will carry half of the chromosomes from the female parent and half from the male parent.
Crossing over and independent assortment are two phenomenons of meiosis due to which genetic diversity occurs and the offsprings born are not exactly similar to the parent cell.
Answer: The four cells that are produced by meiosis has only one of each chromosome. One of these four cells from one parent combines with another from the other parent to produce the offspring. An offspring gets half its chromosomes from each parent. But the exact combination of chromosomes it gets from each parent is random. So, each offspring ends up with a unique set of genes different from its parents and other offspring.
OB 1s22s22p63s23p6
OC 1s22s22p63s2305
OD 1s22s²2p63s23d10452
Answer:
1s2 2s2 2p6 3s2 3d5 is a pseudo-noble-gas electron configuration
Explanation:
It is the technetium with atomic number 43. Being the lightest element having isotopes with all radioactive and no one are more stable as compared to that of technetium which is in fully ionised state i.e. 97 Tc. This element is mostly used for gamma ray emission in medical treatment. Also found to be used as corrosion inhibitor in case of steel, when present in small amount gives better result. This metal is silver grey colour that is found to discoloration when comes in contact with moist air. Its isotopes are radioactive.
Answer:
1s2 2s2 2p6 3s2 3p6 3d10
Explanation:
A pseduo noble gas configuration refers to charged species with electron configurations that are almost identical to that of one of the noble gases.
The noble gas (n-1)d^10 (where n refers to the principal quantum number of the outer s orbital) configuration of ions is commonly known as a pseudo noble gas configuration. The configuration stated in the answer is for Cu^+ ion. n in the case of Cu^+ ion is 4(since copper metal has a 4s1 level).
Note that; 1s2 2s2 2p6 3s2 3p6 is the electron configuration for argon, followed by 3d^10. Hence our definition for a pseudo noble gas.
0.06 L of KOH with unknown concentration is placed in a flask with bromthymol blue indicator. A solution of 0.20 M
H2504 is dripped into the KOH solution. After exactly 0.017 L of H2SO4 is added, the Indicator changes from blue to
yellow. What is the concentration of the KOH? You must show all of your work to earn credit. (4 points)
H2SO4 + 2KOH → K2SO4 + 2H20
Answer:
Explanation:
1. Reaction
2. Mole ratio
3. Sulfuric acid
4. Potassium hydroxide