B. stroke.
C. kidney damage.
D. all of the above.
Answer:
15.63
Explanation:
250g O2 x 1 mol O2 x 2mol HgO / 32 g O2 x 1 mol O2
The number of moles in 987 grams of Ra(OH)2 = 3.8 moles
Ra = 226g
O= 16g
H = 1
Therefore molar mass of Ra(OH)2= 226+ (16+1)×2
= 260g/mol
The molar mass of Ra(OH)2 = 260g/mol
Thus means that 260g of Ra(OH)2 makes up 1 mole
Therefore, 987 g = X moles
Make X moles the subject of formula,
X mole = 987/260
= 3.8 moles
Therefore, the number of moles in 987 grams of Ra(OH)2 = 3.8 moles
Learn more about molar mass here:
Answer : 3.79 moles are in 987 grams of .
Solution : Given,
Mass of = 987 g
Molar mass of = 260 g/mole
Now we have to calculate the moles of .
Formula used :
Now put all the given values in this formula, we get the moles.
Therefore, 3.79 moles are in 987 grams of .
Answer:homogeneous mixture
Explanation:
Answer:
i) increase
ii) decrease
iii) remain the same
iv) No, because it dissociates completely.
Explanation:
On a 10-fold dilution of a weak acid, the pH will increase because the concentration of hydrogen ions will decrease thereby increasing the pH to close to that of water.
On a 10-fold dilution of a weak base, the pH will decrease due to the removal of hydroxide ions from the solution. This results in the solution having a H closer to that of water.
If one adds a very small amount of strong base to a buffered solution, the pH will remain constant because a buffer solution acts to withstand any change to its pH on the addition of small quantities of either an acid or a base.
A buffer solution cannot be made with a strong acid because thy undergo complete dissociation. Therefore, any small addition of base or acid will result in very large changes in the pH of the solution. A buffer solution is made with a weak acid and its conjugate base or a weak base and its conjugate acid.